Bromine monofluoride (BF) disproportionates to bromine gas and bromine tri- and pentafluorides. Use the following to find ΔHorxnfor the decomposition of BrF to its elements:

3BrF(g)Br2(g)+BrF3(l)ΔHorxn=-125.3KJ\hfill5BrF(g)2Br2(g)+BrF5(l)ΔHorxn=-166.1KJ\hfillBrF3(l)+F2(g)BrF5(l)ΔHorxn=-158.0KJ\hfill

Short Answer

Expert verified

Enthalpy of reaction followed as:

8BrF(g)2BrF3(l)+3Br2g+F2(g)ΔHorxn=-138.4KJ

Step by step solution

01

Enthalpy of reaction

It is defined as the heat of the action which is calculated to find out how much energy is required by the reaction to convert it’s one more into products that is equal to the change in energy of the system. a positive value indicates the reaction is endothermic that is heat is required and a negative value indicates the reaction is exothermic that heat is released.

02

Enthalpy of the given reaction

To calculate the enthalpy of reaction when Bromine monofluoride (BF) disproportionates to bromine gas and bromine tri- and pentafluorides followed as:

As given:

As enthalpy is equal to

ΔHorxn=-125.3KJ-166.1KJ+158.0KJ=-138.4KJ

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free