Chapter 3: Q3.104P (page 89)

How many milliliters of 0.383 M HCl are needed to react with 16.2 g of CaCO₃?
$2 H C l (a q) + C a C O_{3} (s) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)$

Short Answer

Expert verified

The amount of solution needed to react with 16.2 g ofCaCO₃is an 846 mL HCl solution.

Step by step solution

Calculating the number of moles of HCl

Calculate the number of moles of HCl needed to react with 16.2 g of Calcium chloride.

$\begin{array}{rcl} M o l e s o f C a C O_{3} & = & 16.2 g C a C O_{3} \times \frac{1 m o l C a C O_{3}}{100.09 g C a C O_{3}} \times \frac{2 m o l H C l}{1 m o l C a C O_{3}} \\ = & 0.324 m o l H C l . \end{array}$

Calculating the volume of solution

Calculate the volume of the solution needed as shown below:

$\begin{array}{rcl} V o l u m e o f s o l u t i o n & = & \frac{0.324 m o l H C l}{0.383 \frac{m o l H C l}{L s o \ln}} \\ = & 0.846 L s o l u t i o n o r 846 m L s o l u t i o n . \end{array}$

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How many milliliters of 0.383 M HCl are needed to react with 16.2 g of CaCO₃?
$2 H C l (a q) + C a C O_{3} (s) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)$

Short Answer

Step by step solution

Calculating the number of moles of HCl

Calculating the volume of solution

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How many milliliters of 0.383 M HCl are needed to react with 16.2 g of CaCO3?2HCl(aq)+CaCO3(s)→CaCl2(aq)+CO2(g)+H2O(l)

Short Answer

Step by step solution

Calculating the number of moles of HCl

Calculating the volume of solution

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Ionic and Molecular Compounds

Chemical Analysis

Kinetics

Chemical Reactions

Inorganic Chemistry

Study anywhere. Anytime. Across all devices.

How many milliliters of 0.383 M HCl are needed to react with 16.2 g of CaCO₃?
$2 H C l (a q) + C a C O_{3} (s) \to C a C l_{2} (a q) + C O_{2} (g) + H_{2} O (l)$