Chapter 3: Q.3.105P (page 89)

How many grams of NaH₂PO₄ are needed to react with 43.74 mL of 0.285 M NaOH?
$N a H_{2} P O_{4} (s) + 2 N a O H (a q) \to N a_{3} P O_{4} (a q) + 2 H_{2} O (l)$

Short Answer

Expert verified

The mass of NaH₂PO₄needed to reactwith 43.74 mL of 0.285 M NaOHis 0.747 g of NaH₂PO₄.

Step by step solution

Calculating the number of moles of HCl

Calculate the number of moles of HCl needed to react with 43.74 mL of sodium hydroxide.

$\begin{array}{rcl} M o l e s o f N a H_{2} P O_{4} & = & 43.74 \times 10^{- 3} L s o \ln \times \frac{0.285 m o l H C l}{1 L s o \ln} \times \frac{1 m o l N a H_{2} P O_{4}}{2 m o l N a H_{2} P O_{4}} \\ = & 6.23 \times 10^{- 3} m o l N a H_{2} P O_{4} . \end{array}$

Calculating the number of moles

Calculate the mass of NaH₂PO₄as shown below:

$\begin{array}{rcl} M a s s o f N a H_{2} P O_{4} & = & 6.23 \times 10^{- 3} m o l N a H_{2} P O_{4} \times \frac{119.98 g N a H_{2} P O_{4}}{1 m o l N a H_{2} P O_{4}} \\ = & 0.747 g N a H_{2} P O_{4} . \end{array}$

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How many grams of NaH₂PO₄ are needed to react with 43.74 mL of 0.285 M NaOH?
$N a H_{2} P O_{4} (s) + 2 N a O H (a q) \to N a_{3} P O_{4} (a q) + 2 H_{2} O (l)$

Short Answer

Step by step solution

Calculating the number of moles of HCl

Calculating the number of moles

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How many grams of NaH2PO4 are needed to react with 43.74 mL of 0.285 M NaOH?NaH2PO4(s)+2NaOH(aq)→Na3PO4(aq)+2H2O(l)

Short Answer

Step by step solution

Calculating the number of moles of HCl

Calculating the number of moles

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Kinetics

The Earths Atmosphere

Making Measurements

Nuclear Chemistry

Chemistry Branches

Organic Chemistry

Study anywhere. Anytime. Across all devices.

How many grams of NaH₂PO₄ are needed to react with 43.74 mL of 0.285 M NaOH?
$N a H_{2} P O_{4} (s) + 2 N a O H (a q) \to N a_{3} P O_{4} (a q) + 2 H_{2} O (l)$