Chapter 3: Q3.106P (page 89)
How many grams of solid barium sulfate form when 35.0 mL of 0.160 M barium chloride reacts with 58.0 mL of 0.065 M sodium sulfate? Aqueous sodium chloride forms also.
Short Answer
When a 35.0 mL of 0.160 M barium chloride reacts with a 58.0 mL of 0.065 M sodium sulfate, 0.88 g of BaSO4will form.