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Chapter 3: Q3.136CP (page 138)

Calculate each of the following quantities:Number of atoms in 0.0015 mol of fluorine gas

Short Answer

Expert verified

According to the question, there are 0.0015 mole of F atoms, and then we have 0.0015´6.022´1023 atoms.

So final answer is 0.009033´1023

Or, 9.033´1026 of F atoms

But for calculating F2diatomic molecules then we have, 9.033´1026´2 = 18.066´1026 =1.81´1021 atoms.

Step by step solution

01

Step1. Number of atoms present.

If there is one mole of F atoms, then there are 6.022140857´1023atoms.

Fluorine can form diatomic molecules so there we have F2 atoms twice as many atoms.

According to the question, there are 0.0015 mole of F atoms, and then we have 0.0015´6.022´1023 atoms.

So final answer is 0.009033´1023

Or, 9.033´1026 of F atoms

But for calculating F2diatomic molecules then we have, 9.033´1026´2 = 18.066´1026 =1.81´1021 atoms.

02

Step2. Final calculation.

If there is one mole of F atoms, then there are 6.022140857´1023atoms.

Fluorine can form diatomic molecules so there we have F2 atoms twice as many atoms.

According to the question, there are 0.0015 mole of F atoms, and then we have 0.0015´6.022´1023 atoms.

So final answer is 0.009033´1023

Or, 9.033´1026 of F atoms

But for calculating F2diatomic molecules then we have, 9.033´1026´2 = 18.066´1026 =1.81´1021 atoms.

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