Acetaminophen (below)is a popular nonaspirin, “over-thecounter” pain reliever. What is the mass % of each element in acetaminophen?

Short Answer

Expert verified

The final mass % each element is:

C = 71.1%

H = 6.7%

N = 10.4%

O = 11.8%

The molecular formula isC8H9N02

Step by step solution

01

Determine the Preliminary formula of the compound

This is the structure of the molecule and has the molecular formulaC8H9N02

It has 8 C, 9 H, 1N, and 2O, for each element we have to calculate the % of the element.

02

Calculation of the mass % of the C in acetaminophen

The mass % of the element is:

mass%ofelement=massofelementin1moleofcompoundmassof1moleofcompound×100%

The mass of 1 mole of compound is:

1moleofcompound=8×(12.011g)+9×(1.001g)+14.007g+2+(15.999g)=135.166g

Thus, the mass % of C is calculated as:

%C=8×(12.011)135.166×100%=71.1%

03

Determine the mass % of the H in acetaminophen

The mass % of H is:

%H=9(1.008)135.166×100%=6.7%

04

Determine the mass % of the N in acetaminophen

%H=14.009135.166×100%=10.4%

05

Determine the mass % of the O in acetaminophen

The mass % of O is:

%O=2×(15.999)135.166×100%=11.8%

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