Helium is the lightest noble gas and the second most abundant element (after hydrogen) in the universe.
(a) The radius of a helium atom is 3.1×10-11m; the radius of its nucleus is 2.5×10-15 m. What fraction of the spherical atomic volume is occupied by the nucleus (V of a sphere =4/3 πr3)?
(b) The mass of a helium-4 atom is 6.64648X10-24 g, and each of its two electrons has a mass of 9.10939×10-28 g. What fraction of this atom's mass is contributed by its nucleus?

Short Answer

Expert verified
  1. The fraction of the spherical atomic volume isV=5.2410-13or5.2410-10percent
  2. The fraction of the atom mass ism=0.999726or99.9726percent

Step by step solution

01

a. Step 1: Finding the fraction of the spherical atomic volume

The radius of the helium and nucleus can be given as,

r1=2.5×10-15r=3.1×10-11v1nucleus=43r13IIv1nucleus=432.5×10-153v1nucleus=6.54×10-44vatom43r3IIvatom433.1×10-113IIv1atom=1.25×10-31fractionv=v1vfractionv=6.54×10-441.25×10-31fractionv=5.24×10-13or5.24×10-11percent

02

b. Step 2: Finding the fraction of this atom's mass is contributed by its nucleus

The mass of the atom and electron can be denoted as,

matom=6.64648×10-24gm1electron=9.1093910-28g

The electron contains 2 electrons and masses can be sum up.

role="math" localid="1657107198424" m1electrons=1.8219×10-27gm2nucleus=m-m1m2nucleus=6.64648×10-24-1.821910×10-27m2nucleus=6.64466×10-24gfraction=m2mfraction=6.64466×10-246.64648×10-24fractionm=0.999726or99.9726%

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