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Chapter 2: Q155CP (page 88)

The anticancer drug Platinol (Cisplatin), Pt(NH3)2Cl2, reacts with the cancer cell’s DNA and interferes with its growth. (a) What is the mass % of platinum (Pt) in Platinol? (b) If Pt costs \(19/g, how many grams of Platinol can be made for \)1.00 million (assume that the cost of Pt determines the cost of the drug)?

Short Answer

Expert verified

a) The mass % of platinum is65.02%

b) There are approx. 53000 g platinolcan be made for $1 million

Step by step solution

01

Calculating the mass percentage of platinum in platinol

On listing the atomic mass of each element,

Pt=195.08u,N=14u,H=1.01u,CI=35.45u

On adding the atomic mass,

Molecularmass=Pt+2(N+3H)+2CI=195.08+2(14+31.01+235.45)=300.04amu

On solving the mass percentage of platinum,

%massPt=195.08300.04×100%=65.02%

02

Calculating the amount of platinol made of $1 M

For 1 g the cost is $19 then in 1M, i.e., $1000000 platinol made will be

1g$19×1000000=52631.58gplatinol

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