Draw a Lewis structure for (a) ${\mathbf{CH}}_4\mathbf{S}$; (b) ${\mathbf{S}}_2{\mathbf{Cl}}_2$; (c) ${\mathbf{CHCl}}_3$.

• In this molecule, the Carbon requires four electrons to fulfil octet which will be provided by 3 H-atom and 1 S-atom then one electron also shared by C-atom to fulfil its duplet.
• In Lewis structure, the C needs 4 electrons and 3 H-atom will provide 3 electrons and 1 Electron from Sulphur to fulfil the C-atom octet. Here, Sulphur gets one electron from C-atom itself and one electron from H-atom to fulfil its octet also.
• ${\mathrm{CH}}_4\mathrm{S}$ is a Tetrahedral structure.

In this molecule, S-atom requires 2 electrons to fulfil its octet which is given by one S-atom and one Cl-atom. Cl-atom requires one electron to fulfil its octet. The Lewis structure forms a linear shape forming a single bond.

${\mathrm{S}}_2{\mathrm{Cl}}_2$ is a Linear structure.

In this molecule, the C-atom is the central atom which requires 4 electrons to fulfil the octet and it is provided by 3 H-atom and 1 Cl-atom. Now, H-atom also requires only one electron to fulfil duplet and Cl-atom also require 1 electron to fulfil its octet using pair of an electron in the Lewis structure.

${\mathrm{CHCl}}_3$ is a Tetrahedral structure.