Chapter 23: Q102P (page 1022)

Rank the following in order of increasing $∆$ and energy of light absorbed: ${[Cr {({NH}_{3})}_{6}]}^{3 +}, {[Cr {(H_{2} O)}_{6}]}^{3 +}, {[Cr {({NO}_{2})}_{6}]}^{3 +}$

Short Answer

Expert verified

The final answer in increasing order is: ${[Cr {(H_{2} O)}_{6}]}^{3 +} < {[Cr {({NH}_{3})}_{6}]}^{3 +} < {[Cr {({NO}_{2})}_{6}]}^{3 +}$

Step by step solution

Given Information

Given compounds are:

${[Cr {({NH}_{3})}_{6}]}^{3 +}, {[Cr {(H_{2} O)}_{6}]}^{3 +}, {[Cr {({NO}_{2})}_{6}]}^{3 +}$

Concept Introduction

The stronger field the ligand is, the bigger the energy of light absorbed. Spectrochemical series (from weak-field to strong-field ligands):

$I^{-} < {Cl}^{-} < F^{-} < {OH}^{-} < H_{2} O < {SCN}^{-} < {NH}_{3} < en < {NO}_{2}^{-} < {CN}^{-} < CO$

Solution

We can now quickly formulate the answer to this problem using the spectrochemical series and the information above:

${[Cr {(H_{2} O)}_{6}]}^{3 +} < {[Cr {({NH}_{3})}_{6}]}^{3 +} < {[Cr {({NO}_{2})}_{6}]}^{3 +}$

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Rank the following in order of increasing $∆$ and energy of light absorbed: ${[Cr {({NH}_{3})}_{6}]}^{3 +}, {[Cr {(H_{2} O)}_{6}]}^{3 +}, {[Cr {({NO}_{2})}_{6}]}^{3 +}$

Short Answer

Step by step solution

Given Information

Concept Introduction

Solution

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Rank the following in order of increasing∆and energy of light absorbed:[Cr(NH3)6]3+,[Cr(H2O)6]3+,[Cr(NO2)6]3+

Short Answer

Step by step solution

Given Information

Concept Introduction

Solution

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Nuclear Chemistry

Inorganic Chemistry

Making Measurements

Chemical Analysis

Physical Chemistry

Study anywhere. Anytime. Across all devices.

Rank the following in order of increasing $∆$ and energy of light absorbed: ${[Cr {({NH}_{3})}_{6}]}^{3 +}, {[Cr {(H_{2} O)}_{6}]}^{3 +}, {[Cr {({NO}_{2})}_{6}]}^{3 +}$