Chapter 23: Q103P (page 1022)

Rank the following in order of decreasing $(∆)$ and energy of light absorbed: ${[Cr {(en)}_{3}]}^{3 +}, {[Cr {(CN)}_{6}]}^{3 -}, {[{CrCl}_{6}]}^{3 -}$

Short Answer

Expert verified

The final answer in decreasing order is ${[Cr {(CN)}_{6}]}^{3 -} > {[Cr {(en)}_{3}]}^{3 +} > {[{CrCl}_{6}]}^{3 -}$

Step by step solution

Given Information

Given compounds are

${[Cr {(en)}_{3}]}^{3 +} {[Cr {(CN)}_{6}]}^{3 -} {[{CrCl}_{6}]}^{3 -}$

Concept Introduction

The stronger field the ligand is, the bigger the energy of light absorbed. Spectrochemical series (from weak-field to strong-field ligands):

$I^{-} < {Cl}^{-} < F^{-} < {OH}^{-} < H_{2} O < {SCN}^{-} < {NH}_{3} < en < {NO}_{2}^{-} < {CN}^{-} < CO$

Solution

We can now quickly formulate the answer to this problem using the spectrochemical series and the information above:

${[Cr {(CN)}_{6}]}^{3 -} > {[Cr {(en)}_{3}]}^{3 +} > {[{CrCl}_{6}]}^{3 -}$

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Rank the following in order of decreasing $(∆)$ and energy of light absorbed: ${[Cr {(en)}_{3}]}^{3 +}, {[Cr {(CN)}_{6}]}^{3 -}, {[{CrCl}_{6}]}^{3 -}$

Short Answer

Step by step solution

Given Information

Concept Introduction

Solution

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Rank the following in order of decreasing(∆)and energy of light absorbed:[Cren3]3+,[CrCN6]3-,[CrCl6]3-

Short Answer

Step by step solution

Given Information

Concept Introduction

Solution

One App. One Place for Learning.

Most popular questions from this chapter

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Rank the following in order of decreasing $(∆)$ and energy of light absorbed: ${[Cr {(en)}_{3}]}^{3 +}, {[Cr {(CN)}_{6}]}^{3 -}, {[{CrCl}_{6}]}^{3 -}$