Chapter 23: Q42 P (page 1059)

Use the following data to determine if Cr²⁺(aq)can be prepared by the reaction ofwith Cr²⁺(aq):
$\begin{array}{rcl} C r^{3 +} (a q) + e^{-} C r^{2 +} (a q) E^{0} & = & - 0.41 V \\ C r^{3 +} (a q) + 3 e^{-} C r (s) E^{0} & = & - 0.74 V \\ C r^{2 +} (a q) + 2 e^{-} C r (s) E^{0} & = & - 0.91 V \end{array}$

Short Answer

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$C r_{(a q)}^{2 +}$ can be formed from Cr_(a) and role="math" localid="1663393665913" width="41" height="30">Cr(aq)3+because the resulting $E_{e n l l}^{o}$ is positive.

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Definition of Coordination Compound

A coordination complex consists of a central atom or ion, which is typically metallic and is termed the coordination centre, and a surrounding array of bound molecules or ions, that are successively referred to as ligands or complexing agents.

Solve the given statements

Cr_(o) Is oxidized to $C r_{(a n)}^{3 +}$ , therefore it is the anode

role="math" localid="1663393826855" $E_{h a l f - o u t}^{o} = - 0.74 . C r_{(a)} \to C r_{(a q)}^{3 +} + 3 e^{-}$

Cr³⁺ is then reduced to Cr²⁺, therefore it is at the cathode.

$E_{h a l f}^{o} - a n = - 0.41 C r_{(a q)}^{3 +} + e^{-} \to C r_{(a)}^{2 +}$

Overall reaction: $C r_{(s)} + 2 C r_{(a)}^{3 +} \to 3 C r_{(a (q)}^{2 +}$

$E_{o u l}^{0} = E_{r e d u c t i o n}^{0} - E_{o x i d a t i o n}^{0} E_{c e l l}^{0} = E_{c a t h o d e}^{0} - E_{a n o d e}^{0} E_{c e l l}^{0} = - 0.41 - (- 0.74) E_{c e l l}^{a} = 0.35 V$

The E_cell is positive, therefore the reaction can proceed spontaneously.

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Definition of Coordination Compound

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Use the following data to determine if Cr2+(aq)can be prepared by the reaction ofwith Cr2+(aq):Cr3+(aq)+e-Cr2+(aq)E0=-0.41VCr3+(aq)+3e-Cr(s)E0=-0.74VCr2+(aq)+2e-Cr(s)E0=-0.91V

Short Answer

Step by step solution

Definition of Coordination Compound

Solve the given statements

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Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Physical Chemistry

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Ionic and Molecular Compounds

Organic Chemistry

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The Earths Atmosphere

Study anywhere. Anytime. Across all devices.