With its components in their standard states, a certain reaction is spontaneous only at high T. What do you know about the signs ofrole="math" localid="1663368103423" ΔHoandΔSo? Describe a process for which this is true.

Short Answer

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Both, ΔHrxn>0and ΔSsys>0. The entropy of the surroundings is negative: ΔSsurr<0.

An example of such a process – is the evaporation of water or melting of metal.

Step by step solution

01

Concept Introduction.

Entropy is a measure of a system's unpredictability or disorder in general.

Entropy is a thermodynamic property that describes how a system behaves in terms of temperature, pressure, entropy, and heat capacity.

02

Signs of ΔHo and ΔSo.

In this case, ΔHrxno>0- the reaction is endothermic (heat is absorbed from the surroundings). Since we remove the heat from the surroundings, theΔSsurr<0as the particles have less energy and move less freely, decreasing the surroundings disorder (entropy).

As the heat is consumed, the entropy of the system increases:ΔSsys>0. The entropy of the system is positive and Temperature too (in Kelvin, the temperature scale is positive).

The negative Gibb's free energy change corresponds to the spontaneous reaction –

ΔG=ΔH-T·ΔSsys<0

So, to make the ΔG<0, the ΔH<<T·ΔSsys.

At high temperatures, this condition is satisfied –

ΔG=ΔH(>0)-Thigh·ΔSsys(>0)ΔG<<0

03

Example of the process.

An example of such a process can be the evaporation of water and the melting of metal. The evaporation occurs only when the temperature is high enough to allow the water molecules to break out from the bulk and surface, connected via an intermolecularbond. Similarly, the metallic lattice corresponds to metal atoms tightly attached to each other - so only at a really high temperature, the metal lattice can be broken (for example, gold melting).

Therefore, both entropy and heat are zero. An example of the process is the evaporation of water.

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