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Chapter 4: Q126CP (page 183)

Magnesium is used in lightweight alloys for airplane bodies and other structures. The metal is obtained from seawater in a process that includes precipitation, neutralization, evaporation, and electrolysis. How many kilograms of magnesium can be obtained from 1.00 km3 of seawater if the initial Mg2+ concentration is 0.13% by mass (dof seawater = 1.04 g/mL)?

Short Answer

Expert verified

The mass of magnesium is 1.35x109 kg.

Step by step solution

01

Determination of volume of sea water.

Let us take 100 g sea water, the mass of Mg+2 will be 0.13 g

The volume of sea water containing 0.13 g Mg+2 is,

Volume=massofseawaterdensityofseawater=100g1.04g/mL

The given volume for is 1 km3. Conversion of given volume into mL is,

1km3×(103m1km)×(102cm31m)×(1ml1cm3)=1015mL

02

Determination of mass of magnesium

The mass of magnesium that can be obtained from 1015mL of sea water is,

MassofMg+2=1015mL×0.13gMg2+96.15mLseawater=1.35×1012g=1.35×109kg

Thus, the mass of magnesium is 1.35x109 kg.

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