An auto mechanic spills 88 mL of 2.6 M H2SO4 solution from a rebuilt auto battery. How many milliliters of 1.6 M NaHCO3 must be poured on the spill to react completely with the sulfuric acid?

Short Answer

Expert verified

286 ml of1.6 M NaHCO3 must be poured on the spill to react completely with the sulfuric acid.

Step by step solution

01

Step 1:first write down the balanced molecular equation:

2NaHCO3(aq)+H2SO4(aq)Na2SO4(aq)+2H2CO3(aq)

02

To find out the volume of NaHCO3 poured to react completely with the sulfuric acid, first, we have to calculate the moles of NaHCO3:

Given values are:

volumeofstandard2.6MH2SO4solution=88mlvolumeofNaHCO3=1.6M

Moles of NaHCO3is:

molesofNaHCO3=(88mlH2SO4)(1lit1000ml)(2.6molH2SO41litH2SO4solution)(2molNaHCO31molH2SO4)=0.4576molNaHCO3

The volume of NaHCO3 poured to react completely with the sulfuric acid:

volumeofNaHCO3=molesofNaHCO3molarityofNaHCO3

=0.4576molNaHCO3(1.6molNaHCO31litNaHCO3)

=0.286litNaHCO3=286mlNaHCO3

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