Chapter 4: Q4.56P (page 180)

One of the first steps in the enrichment of uranium for use in nuclear power plants involves a displacement reaction between ${UO}_{2} ?$ and aqueous HF:
${UO}_{2} (s) + HF (aq) \to {UF}_{4} (s) + H_{2} O (l) (unbalanced)$
How many liters of 2.40 M HF will react with 2.15 kg of ${UO}_{2} ?$

Short Answer

Expert verified

13.27 lit liters of 2.40 M HF will react with 2.15 kg of ${UO}_{2}$ .

Step by step solution

Write down the balanced molecular equation

The reaction is shown below.

${UO}_{2} (s) + 4 HF (aq) \to {UF}_{4} (s) + 2 H_{2} O (l)$

Calculate the moles of HF

Given values are:

The mass of = 2.15 kg and the molarity of HF = 2.40 M

Moles of HFare:

$\begin{matrix} {number of moles of UO}_{2} = \frac{2.15 kg×1000 g}{270.03} \\ = 7.96 moles \end{matrix}$

One mole of ${UO}_{2}$ react with 4 moles of HF. Therefore,

mole  ratio = \frac{4  moles  HF}{{1  moleUO}_{2}} = 4

Number of moles of HF that reacted with $7.96 moles$ of ${UO}_{2}$ is calculated below.

$Number of molesof HF = 7.96 \times 4 = 31.85$

Calculate the volume of HF

The volume of HF to react completely with 2.15 kg of ${UO}_{2}$

role="math" localid="1658752947679" $\begin{matrix} volume of HF & = & \frac{moles of HF}{molarity of HF} \\ = & \frac{31.85 molHF}{(\frac{2.40 molHF}{1 litHF})} \\ = 13.27 literHF \end{matrix}$

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One of the first steps in the enrichment of uranium for use in nuclear power plants involves a displacement reaction between ${UO}_{2} ?$ and aqueous HF:
${UO}_{2} (s) + HF (aq) \to {UF}_{4} (s) + H_{2} O (l) (unbalanced)$
How many liters of 2.40 M HF will react with 2.15 kg of ${UO}_{2} ?$

Short Answer

Step by step solution

Write down the balanced molecular equation

Calculate the moles of HF

Calculate the volume of HF

One App. One Place for Learning.

Most popular questions from this chapter

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One of the first steps in the enrichment of uranium for use in nuclear power plants involves a displacement reaction between UO2? and aqueous HF:UO2(s)+HF(aq)→UF4(s)+H2O(l)(unbalanced)How many liters of 2.40 M HF will react with 2.15 kg ofUO2?

Short Answer

Step by step solution

Write down the balanced molecular equation

Calculate the moles of HF

Calculate the volume of HF

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Inorganic Chemistry

Organic Chemistry

Chemical Analysis

Ionic and Molecular Compounds

Making Measurements

Chemical Reactions

Study anywhere. Anytime. Across all devices.

One of the first steps in the enrichment of uranium for use in nuclear power plants involves a displacement reaction between ${UO}_{2} ?$ and aqueous HF:
${UO}_{2} (s) + HF (aq) \to {UF}_{4} (s) + H_{2} O (l) (unbalanced)$
How many liters of 2.40 M HF will react with 2.15 kg of ${UO}_{2} ?$