State which of the following species are amphiprotic and write chemical equations illustrating the amphiprotic character of these species.

\({\rm{\;(a)\;N}}{{\rm{H}}_3}\)

\({\rm{\;(b)\;HPO}}_4^ - \)

\({\rm{\;(c)\;B}}{{\rm{r}}^ - }\).

\({\rm{\;(d)\;N}}{{\rm{H}}_4} + \)

\({\rm{\;(e)\;ASO}}_4^{3 - }\).

Short Answer

Expert verified

a) Ammonia is amphiprotic

\(\begin{aligned}{{\rm{N}}{{\rm{H}}_3}(aq) + {{\rm{H}}_2}{\rm{O}}(l) \to {\rm{NH}}_2^ - (aq) + {{\rm{H}}_3}{{\rm{O}}^ + }(aq)}\\{{\rm{N}}{{\rm{H}}_3}(aq) + {{\rm{H}}_2}{\rm{O}}(l) \to {\rm{NH}}_4^ + (aq) + {\rm{O}}{{\rm{H}}^ - }(aq)}\end{aligned}\)

b) \({\rm{HPO}}_4^{2 - }\) is amphiprotic

\(\begin{aligned}{{\rm{HPO}}_4^{2 - }(aq) + {{\rm{H}}_2}{\rm{O}}(l) \to {\rm{PO}}_4^{3 - }(aq) + {{\rm{H}}_3}{{\rm{O}}^ + }(aq)}\\{{\rm{HPO}}_4^{2 - }(aq) + {{\rm{H}}_2}{\rm{O}}(l) \to {{\rm{H}}_2}{\rm{PO}}_4^ - (aq) + {\rm{O}}{{\rm{H}}^ - }(aq)}\end{aligned}\)

c) \(B{r^ - }\)is not amphiprotic

d) \({\rm{NH}}_4^ + \)is also not amphiprotic

e) \({\rm{AsO}}_4^{3 - }\)is not amphiprotic

Step by step solution

01

Amphiprotic species

Amphiprotic species can react as a Bronsted-Lowry's acid (proton donor) and as a base (proton acceptor).

02

Check whether the species are amphiprotic or not

a) Ammonia is amphiprotic. Here \({\rm{N}}{{\rm{H}}_3}\)acts as an acid:

\({\rm{N}}{{\rm{H}}_3}(aq) + {{\rm{H}}_2}{\rm{O}}({\rm{l}}) \to {\rm{NH}}_2^ - (aq) + {{\rm{H}}_3}{{\rm{O}}^ + }(aq)\)

In this equation acts as a base:

\({\rm{N}}{{\rm{H}}_3}(aq) + {{\rm{H}}_2}{\rm{O}}({\rm{l}}) \to {\rm{NH}}_4^ + (aq) + {\rm{O}}{{\rm{H}}^ - }(aq)\)

b) \({\rm{HPO}}_4^{2 - }\) is also amphiprotic and it can be seen in its reactions with water. Here acts like an acid:

.\({\rm{HPO}}_4^{2 - }(aq) + {{\rm{H}}_2}{\rm{O}}({\rm{l}}) \to {\rm{PO}}_4^{3 - }(aq) + {{\rm{H}}_3}{{\rm{O}}^ + }(aq)\).

In following equation acts as a base:

\({\rm{HPO}}_4^{2 - }(aq) + {{\rm{H}}_2}{\rm{O}}({\rm{l}}) \to {{\rm{H}}_2}{\rm{PO}}_4^ - (aq) + {\rm{O}}{{\rm{H}}^ - }(aq)\)

c) \(B{r^ - }\)is not amphiprotic. It can act like a base - proton acceptor, but it cannot be an acid because it does not have any proton to donate.

d) \({\rm{NH}}_4^ + \)is also not amphiprotic. It can act like an acid - proton donor, but it cannot accept any more protons, so it is not a base.

e) \({\rm{AsO}}_4^{3 - }\)is not amphiprotic. It can act like a base - proton acceptor, but it cannot be an acid because it does not have any proton to donate.

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Most popular questions from this chapter

Novocaine, \({C_{13}}{H_{21}}{O_2}\;{N_2}Cl\), is the salt of the base procaine and hydrochloric acid. The ionization constant for procaine is \(7 \times 1{0^{ - 6}}\). Is a solution of novocaine acidic or basic? What are \(\left( {{H_3}{O^ + }} \right),\left( {O{H^ - }} \right)\), and \(pH\) of a \(2.0\% \) solution by mass of novocaine, assuming that the density of the solution is \(1.0\;g/mL\).

Question: Write equations that show \({H_2}PO_4^ - \) acting both as an acid and as a base.

Calculate the concentration of each species present in a \(0.010M\) solution of phthalic acid, \({C_6}{H_4}{\left( {C{O_2}H} \right)_2}\).

\(\begin{array}{*{20}{c}}{{C_6}{H_4}{{\left( {C{O_2}H} \right)}_2}(aq) + {H_2}O(l) \rightleftharpoons {H_3}{O^ + }(aq) + {C_6}{H_4}\left( {C{O_2}H} \right){{\left( {C{O_2}} \right)}^ - }(aq)}&{{K_a} = 1.1 \times 1{0^{ - 3}}} \\ {{C_6}{H_4}\left( {C{O_2}H} \right)\left( {C{O_2}} \right)(aq) + {H_2}O(l) \rightleftharpoons {H_3}{O^ + }(aq) + {C_6}{H_4}{{\left( {C{O_2}} \right)}_2}^{2 - }(aq)}&{{K_a} = 3.9 \times 1{0^{ - 6}}} \end{array}\)

Predict which acid in each of the following pairs is the stronger and explain your reasoning for each. \(\;(a)\;{H_2}O\;or\;HF,\;(b)\;B{(OH)_3}\;or\;Al{(OH)_3},\;(c)\;HSO_3^ - or\;HSO_4^ - ,\;(d)\;N{H_3}\;or\;{H_2}S,\;(e)\;{H_2}O\;or\;{H_2}Te\)

Predict which compound in each of the following pairs of compounds is more acidic and explain your reasoning for each.

  1. \(HSO_4^ - or\; HSeO_4^ - \)
  2. \(N{H_3}\;or\;{H_2}O\)
  3. \(P{H_3}\;or HI\)
  4. \(N{H_3}\;or\;P{H_3}\)
  5. \({H_2}S\;or\;HBr\)
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