The hydronium ion concentration in a sample of rainwater is found to be \(1.7 \times 1{0^{ - 6}}M\) times 25oC. What is the concentration of hydroxide ions in the rainwater?

Short Answer

Expert verified

concentration of hydroxide ion using ionization constant for water is

\(c\left( {O{H^ - }} \right) = 5.8 \times 1{0^{ - 9}}\frac{{mol}}{L}\)

Step by step solution

01

Given Information:

Concentration of the hydronium ions in rain water is \(1.7 \times 1{0^{ - 6}}M\)

The concentration of hydroxide ions can be found from \(pOH\) with the equation\(c\left( {O{H^ - }} \right) = {10^{ - pOH}}mol{L^{ - 1}}\).

02

To find the concentration of the hydroxide ions in the rain water:

Concentration of the hydronium ion is

\(c\left( {{H_3}{O^ + }} \right) = 1.7 \times 1{0^{ - 6}}\frac{{mol}}{L}\)

To calculate concentration of hydroxide ion using ionization constant for water

\({K_w} = c\left( {{H_3}{O^ + }} \right) \times c\left( {O{H^ - }} \right)\)

\(c\left( {O{H^ - }} \right) = \frac{{{K_w}}}{{c\left( {{H_3}{O^ + }} \right)}}\)

Ionization constant for water is\(1.0 \times 1{0^{ - 14}}\)

\(c\left( {O{H^ - }} \right) = \frac{{1.0 \times 1{0^{ - 14}}}}{{1.7 \times 1{0^{ - 6}}}}\)

\(c\left( {O{H^ - }} \right) = 5.8 \times 1{0^{ - 9}}\frac{{mol}}{L}\)

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