The active ingredient formed by aspirin in the body is salicylic acid, \({C_6}{H_4}OH\left( {C{O_2}H} \right)\). The carboxyl group \(\left( { - C{O_2}H} \right)\)acts as a weak acid. The phenol group (an OH group bonded to an aromatic ring) also acts as an acid but a much weaker acid. List, in order of descending concentration, all of the ionic and molecular species present in a \(0.001M\) aqueous solution of \({C_6}{H_4}OH\left( {C{O_2}H} \right)\)

Short Answer

Expert verified

All the ionic and molecular species present in a 0.001 M aqueous solution of \({C_6}{H_4}OH\left( {C{O_2}H} \right),\) in the order of descending concentrations are \({H_2}O > {C_6}{H_4}OH\left( {C{O_2}H} \right) > {H^ + } > {C_6}{H_4}OH\left( {CO_2^ - } \right) > {C_6}{H_4}{O^ - }\left( {CO_2^ - } \right) > O{H^ - }.\)

Step by step solution

01

Define strong base

A weak acid is any acid that is not a strong acid. When a weak acid dissociates, the acid becomes stronger.

02

Descending concentrations order

All the ionic and molecular species present in a 0.001 M aqueous solution of\({C_6}{H_4}OH\left( {C{O_2}H} \right)\)in the order of descending concentrations are\({H_2}O > {C_6}{H_4}OH\left( {C{O_2}H} \right) > {H^ + } > {C_6}{H_4}OH\left( {CO_2^ - } \right) > {C_6}{H_4}{O^ - }\left( {CO_2^ - } \right) > O{H^ - }.\)

After the water ionized form of salicylic acid it is weak acid and there is more molecule dissociate. This is followed by the salicylic acid, which have \({H^ + }\) ions and have a higher concentration of the ionized form. Both \({C_6}{H_4}OH\left( {C{O_2}H} \right)\;and {C_6}{H_4}OH\left( {CO_2^ - } \right)\) molecules can release a proton. After \({H^ + }\)ions, we have \({C_6}{H_4}OH\left( {CO_2^ - } \right), followed by \;{C_6}{H_4}{O^ - }\left( {CO_2^ - } \right)\). The \(C{O_2}H\) group is a stronger acid than the \(OH\) group and likely to ionize. \(O{H^ - }\) ions are a weak acidic solution. Both \(O{H^ - } and\;{H^ + }\) ions in every solution’s relative concentration determines whether a solution is acidic or basic.

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Most popular questions from this chapter

From the equilibrium concentrations given, calculate \({K_a}\)for each of the weak acids and \({K_b}\)for each of the weak bases.

\(\begin{aligned}(a)N{H_3}:\left( {O{H^ - }} \right) = 3.1 \times 1{0^{ - 3}}M\left( {NH_4^ + } \right) = 3.1 \times 1{0^{ - 3}}M;\left( {N{H_3}} \right) = 0.533M;\\(b)HN{O_2}:\left( {{H_3}{O^ + }} \right) = 0.011M;\left( {NO_2^ - } \right) = 0.0438M;\left( {HN{O_2}} \right) = 1.07M;\\(c){\left( {C{H_3}} \right)_3}\;N:\left( {{{\left( {C{H_3}} \right)}_3}\;N} \right) = 0.25M;\left( {{{\left( {C{H_3}} \right)}_3}N{H^ + }} \right) = 4.3 \times 1{0^{ - 3}}M;\left( {O{H^ - }} \right) = 4.3 \times 1{0^{ - 3}}M;\\(d)N{H_4} + :\left( {N{H_4} + } \right) = 0.100M;\left( {N{H_3}} \right) = 7.5 \times 1{0^{ - 6}}M;\left( {{H_3}{O^ + }} \right) = 7.5 \times 1{0^{ - 6}}M\end{aligned}\)

\(\begin{aligned}\left( {N{H_3}} \right) = 7.5 \times 1{0^{ - 6}}M\\\left( {{H_3}{O^ + }} \right) = 7.5 \times 1{0^{ - 6}}M\end{aligned}\)

What is the conjugate acid of each of the following? What is the conjugate base of each?

  1. \({\rm{O}}{{\rm{H}}^{^ - }}\)
  2. \({{\rm{H}}_2}O\)
  3. \({\rm{HCO}}_3^ - \)
  4. \({\rm{N}}{{\rm{H}}_3}\)
  5. \({\rm{HSO}}_4^ - \)
  6. \({{\rm{H}}_2}{\rm{PO}}_4^ - \)
  7. \({\rm{H}}{{\rm{S}}^ - }\)
  8. \({{\rm{H}}_5}{{\rm{N}}_2}^ + \)

What is the conjugate acid of each of the following? What is the conjugate base of each?

\({\rm{a) }}{{\rm{H}}_2}S\)

\({\rm{b) }}{{\rm{H}}_2}{\rm{PO}}_4^ - \)

\({\rm{c) P}}{{\rm{H}}_3}\)

\({\rm{d) }}H{S^ - }\)

\({\rm{(e)HSO}}\;_3^ - \)

\({\rm{\;(f)\;}}{{\rm{H}}_3}{{\rm{O}}_2}^ + \)

\({\rm{\;(g)\;}}{{\rm{H}}_4}{{\rm{N}}_2}\)

\({\rm{\;(h)\;C}}{{\rm{H}}_3}{\rm{OH}}\)

Calculate the concentration of all solute species in each of the following solutions of acids or bases. Assume that the ionization of water can be neglected, and show that the change in the initial concentrations can be neglected. Ionization constants can be found in Appendix H and Appendix I.

\((a) 0.0092M HClO\), a weak acid

\((b) 0.0784M {C_6}{H_5}N{H_2}\), a weak base

\((c) 0.0810{\rm{ }}M HCN\), a weak acid

\((d) 0.11M{\left( {C{H_3}} \right)_3}\;N\), a weak base

\((e) 0.120MFe\left( {{H_2}O} \right)_6^{2 + }\), a weak acid \({K_a} = 1.6 \times 1{0^{ - 7}}\)

Which of the following concentrations would be practically equal in a calculation of the equilibrium concentrations in a \(0.134 - M\) solution of \({H_2}C{O_3}\), a diprotic acid: \(\left( {{H_3}{O^ + }} \right),\left( {O{H^ - }} \right),\left( {{H_2}C{O_3}} \right),\left( {HCO_3^ - } \right)\left( {CO_3^{2 - }} \right)?\) No calculations are needed to answer this question.

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