Chapter 14: QCYL (page 768)
Check your learning the ion product of water at \(8{0^^\circ }C\) is \(2.4 \times 1{0^{ - 13}}.\) What are the concentrations of hydronium and hydroxide ions in pure water at\(8{0^^\circ }C\) ?
Short Answer
Kw is called the equilibrium constant of water means dissociation and ionization of water at 25 Celsius which accounts to about 10-14 at 25 degrees centigrade.
\(\left[ {{H^ + }} \right] = {K_w}\left[ {{H^ + }} \right] = \sqrt {2.44 \times 1{0^{ - 13}}} \)
\(\left[ {O{H^ - }} \right] = 4.94 \times 1{0^{ - 7}}moles/lit\)