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Chapter 8: Q46E (page 451)

True or false: Boron contains \({\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{1}}}\)valence electrons, so only one \({\rm{p}}\)- orbital is needed to form molecular orbitals.

Short Answer

Expert verified

The given statement is false.

Step by step solution

01

Molecular orbitals

The molecular orbital of an atom can be formed by the overlapping of atomic orbitals. During this process, the valence orbitals will participate.

02

Step 2: \({{\bf{B}}_{\bf{2}}}\) molecule

The molecular orbitals of\({B_2}\)are formed by the overlapping of valence atomic orbitals of each boron atom.

The valence orbitals in the boron are both 2s and 2p.

Hence, both 2s and 2p will participate in molecular orbital formation.

The given statement is false.

Molecular orbital diagram for \({B_2}\)

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Most popular questions from this chapter

Draw the orbital diagram for carbon in showing how many carbon atom electrons are in each orbital.

Sketch the distribution of electron density in the bonding and antibonding molecular orbitals formed from two S orbitals and from two P orbitals.

In addition to \({\rm{N}}{{\rm{F}}_{\rm{3}}}\), two other fluoro derivatives of nitrogen are known: \({{\rm{N}}_{\rm{2}}}{{\rm{F}}_{\rm{4}}}\) and \({{\rm{N}}_{\rm{2}}}{{\rm{F}}_{\rm{2}}}\). What shapes do you predict for these two molecules? What is the hybridization for the nitrogen in each molecule?

Acetic acid, H3CC(O)OH, is the molecule that gives vinegar its odor and sour taste. What is the hybridization of the two carbon atoms in acetic acid?

Sulfuric acid is manufactured by a series of reactions represented by the following equations:

\(\begin{array}{l}{{\rm{S}}_{\rm{8}}}{\rm{(s) + 8}}{{\rm{O}}_{\rm{2}}}{\rm{(g)}} \to {\rm{8S}}{{\rm{O}}_{\rm{2}}}{\rm{(g)}}\\{\rm{2S}}{{\rm{O}}_{\rm{2}}}{\rm{(g) + }}{{\rm{O}}_{\rm{2}}}{\rm{(g)}} \to {\rm{2S}}{{\rm{O}}_{\rm{3}}}{\rm{(g)}}\\{\rm{S}}{{\rm{O}}_{\rm{3}}}{\rm{(g) + }}{{\rm{H}}_{\rm{2}}}{\rm{O(l)}} \to {{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}}{\rm{(l)}}\end{array}\)

Draw a Lewis structure, predict the molecular geometry by VSEPR, and determine the hybridization of sulfur for the following:

(a) circular \({{\rm{S}}_{\rm{8}}}\)molecule

(b) \({\rm{S}}{{\rm{O}}_{\rm{2}}}\)molecule

(c) \({\rm{S}}{{\rm{O}}_{\rm{3}}}\)molecule

(d) \({{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}}\)molecule (the hydrogen atoms are bonded to oxygen atoms)
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