The molecule \({\rm{XC}}{{\rm{l}}_{\rm{2}}}\)has a dipole moment. Is X beryllium or sulfur?

Dipole Moment: The separation of two electrical charges opposite in charge is measured by the dipole moment of any compound. It's calculated by multiplying the product of the two charges by the distance between them. Dipole moment is always shown in the direction of negative to positive charge.

The compound will be \({\rm{BeC}}{{\rm{l}}_{\rm{2}}}\)if X is beryllium. The linear structure of the compound \({\rm{BeC}}{{\rm{l}}_{\rm{2}}}\) .Each Be-Cl bond has the same dipole moment but in the opposite direction. As a result, \({\rm{BeC}}{{\rm{l}}_{\rm{2}}}\)has a net dipole moment of zero.

The compound will be \({\rm{SC}}{{\rm{l}}_{\rm{2}}}\)if X is sulphur.Because of the lone pair of electrons in the S atom, the structure of the \({\rm{SC}}{{\rm{l}}_{\rm{2}}}\)is bent. Each S-Cl dipole moment is equal, but not in the same direction. The compound \({\rm{SC}}{{\rm{l}}_{\rm{2}}}\)has a net dipole moment as a result. As a result, X is Sulfur.

Therefore, the element X is Sulfur.