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Chapter 7: Q73E (page 400)

Question: Complete the following Lewis structure by adding bonds (not atoms), and then indicate the longest bond:

Short Answer

Expert verified

The Lewis Structure with longest \({\rm{C - C}}\) bond is as follows –

Step by step solution

01

Concept Introduction

Chemical bonding is the creation of a chemical compound by forming a chemical link between two or more atoms, molecules, or ions. The atoms in the resultant molecule are held together by chemical bonds.

02

Adding the bonds

Observe the Lewis structure –

Add the single and double bonds wherever required –

Since single bond is longest as compared to double and triple, therefore \({\rm{C - C}}\) is the single bond which is the longest.

Therefore, \({\rm{C - C}}\) are the longest bonds.

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Most popular questions from this chapter

Predict the charge on the monatomic ions formed from the following atoms in binary ionic compounds: (a) \({\rm{P}}\) (b) \({\rm{Mg}}\) (c) \({\rm{Al}}\) (d) \({\rm{O}}\) (e) \({\rm{Cl}}\) (f) \({\rm{Cs}}\).

The molecule \({\rm{XC}}{{\rm{l}}_{\rm{2}}}\)has a dipole moment. Is X beryllium or sulfur?

Use the simulation (http://openstaxcollege.org/l/16MolecPolarity) to perform the following exercises for a real molecule. You may need to rotate the molecules in three dimensions to see certain dipoles. (a) Sketch the bond dipoles and molecular dipole (if any) for O3. Explain your observations. (b) Look at the bond dipoles for NH3. Use these dipoles to predict whether N or H is more electronegative. (c) Predict whether there should be a molecular dipole for NH3 and, if so, in which direction it will point. Check the molecular dipole box to test your hypothesis.

Explain how a molecule that contains polar bonds can be nonpolar.

Identify the atoms that correspond to each of the following electron configurations. Then, write the Lewis symbol for the common ion formed from each atom: (a)\({\text{1}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{p}}^{\text{5}}}\)(b)\({\text{1}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{p}}^{\text{6}}}{\text{3}}{{\text{s}}^{\text{2}}}\)(c)\({\text{1}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{p}}^{\text{6}}}{\text{3}}{{\text{s}}^{\text{2}}}{\text{3}}{{\text{p}}^{\text{6}}}{\text{4}}{{\text{s}}^{\text{2}}}{\text{3}}{{\text{d}}^{{\text{10}}}}\)(d)\({\text{1}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{p}}^{\text{6}}}{\text{3}}{{\text{s}}^{\text{2}}}{\text{3}}{{\text{p}}^{\text{6}}}{\text{4}}{{\text{s}}^{\text{2}}}{\text{3}}{{\text{d}}^{{\text{10}}}}{\text{4}}{{\text{p}}^{\text{4}}}\)(e)\({\text{1}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{p}}^{\text{6}}}{\text{3}}{{\text{s}}^{\text{2}}}{\text{3}}{{\text{p}}^{\text{6}}}{\text{4}}{{\text{s}}^{\text{2}}}{\text{3}}{{\text{d}}^{{\text{10}}}}{\text{4}}{{\text{p}}^{\text{1}}}\).
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