Determine the number of atoms and the mass of zirconium, silicon, and oxygen found in 0.3384 mol of zircon, ZrSiO₄, a semiprecious stone.

0.3384 mol of ZrSiO₄

Molecular weight of ZrSiO₄ = 91 + 28 + 4 x 16 = 183 g/mol

Number of mol of Zr = 0.3384 mol x 1 = 0.3384 mol of Zr

Number of mol of Si = 0.3384 mol x 1 = 0.3384 mol of Si

Number of moles of O = 0.3384 mol x 4 = 1.353 mol of O

1 mol of x = 6.022 x 10 ²³ atoms of x (Avogadro number)

Number of atoms of Zr = 0.3384 mol of Zr x 6.022 x 10 ²³ atoms

= 2.037 x 10 ²³ atoms of Zr

Number of atoms of Si = 0.3384 mol of Si x 6.022 x 10 ²³ atoms

= 2.037 x 10 ²³ atoms of Si

Number of atoms of O = 1.353 mol of O x 6.022 x 10 ²³ atoms

= 8.147 x 10 ²³ atoms of O

Mass of Zr = 0.3384 mol of Zr x 91 g/mol = 30.794 g

Mass of Si = 0.3384 mol of Si x 28 g/mol = 9.475 g

Mass of O = 1.353 mol of O x 16 g/mol = 21.648 g