Chapter 3: Q.25E (page 129)

Determine which of the following contains the greatest mass of aluminum: 122 g of AlPO₄, 266 g of Al₂C₁₆, or 225 g of Al₂S₃.

Short Answer

Expert verified

Greatest mass of Al is in Al₂S₃ = 81 g.

Step by step solution

Determine the number of moles

Given

122 g of AlPO₄

266 g of Al₂C₁₆

225 g of Al₂S₃

Molar mass of AlPO₄ = 2 x 27 + 16 x 12 = 246 g/mol

Molar mass Al₂C₁₆= 27 + 31+ 4 x 16 = 122 g/mol

Molar mass Al₂S₃= 2 x 27 + 3 x 32 = 150 g/mol

Number of mole of AlPO₄ = (122 g) / (122 g/mol) = 1 mol AlPO4

Number of mole of Al₂C₁₆ = (266 g)/(246 g/mol) = 1.081 mol of Al₂C₁₆

Number of mole of Al₂S₃ = (225 g)/(150 g/mol) = 1.5 mol of Al₂S₃

Determine the mass

Mass of Al in AlPO₄ = 1 mol x 27 g/mol = 27 g

Mass of Al in Al₂C₁₆ = 1.081 mol x 54 g/mol = 58.374 g

Mass of Al in Al₂S₃ = 1.5 mol x 54 g /mol = 81 g

Greatest mass of Al is in Al₂S₃

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Determine which of the following contains the greatest mass of aluminum: 122 g of AlPO₄, 266 g of Al₂C₁₆, or 225 g of Al₂S₃.

Short Answer

Step by step solution

Determine the number of moles

Determine the mass

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Short Answer

Step by step solution

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Determine the mass

One App. One Place for Learning.

Most popular questions from this chapter

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