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Chapter 3: Q.26PE (page 129)

Diamond is one form of elemental carbon. An engagement ring contains a diamond weighing 1.25 carats (1 carat = 200 mg). How many atoms are present in the diamond?

Short Answer

Expert verified

1.254 x 1022 atoms of C are present in the diamond.

Step by step solution

01

Determine number of moles

Mass = 1.25 carats (1 carat = 200 mg)

Actual Weight of the diamond = 1.25 x 200 = 250 mg = 0.250 g (1 g = 1000mg so 1 mg = 0.001 g)

Now we have to calculate the mole of C

Moles of C = (0.250 g) / (12 g/mol) = 0.02083 mol of C

02

Determine number of atoms

Now we got mol of C. So as we know

1 mol of C = 6.022 x 1023 atoms of C

0.02083 mol C =0.02083 x 6.022 x 1023 atoms of C

= 0.1254 x 1023 atoms of C

= 1.254 x 1022 atoms of C

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