How many grams of CaCl2 (110.98 g/mol) are contained in 250.0 mL of a 0.200-Msolution of calcium chloride?

Short Answer

Expert verified

5.55 g CaCl2 are contained in 250.0 mL of a 0.200-Msolution of calcium chloride

Step by step solution

01

Given data

Molecular weight of CaCl2 = 110.98 g/mol

Molarity of CaCl2 = 0.200 M

Volume = 250 mL = 0.250 L (1L = 1000 mL )

02

Determine the mass

Molarity = Moles of CaCl2 / Liters of solution

Plugging respective values in the above formula

0.200 M = Moles of CaCl2/ 0.250 L

Moles of CaCl2 = 0.200 x 0.250 = 0.05 mole

Number of mole = Mass / Molecular weight

Mass = 0.05 mole x 110.98

= 5.549 g

= 5.55 g CaCl2

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