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Chapter 3: Q80 E (page 172)

Find the molarity of 40.0% by the mass aqueous solution of sulphuric acid H2SO4 for which the density is 1.3057g/ml.

Short Answer

Expert verified

The molarity of 40.0% by a mass aqueous solution of sulphuric acid is 5.33mol/L.

Step by step solution

01

Step 1- Given data

Density- 1.3057g/ml

Mass percent=40.0%

02

Step 2- Calculating molarity

From density, we can say that there is 1305.7g of solution and only 40% is sulphuric acid

= 0.40 x 1305.7 = 522.28g

So, there is 522.28g of sulphuric acid in 40% of sulphuric acid solution

Moles of sulphuric acid= given mass/molar mass

= 522.28g/98.079g

=5.33mol

So, in 1L of solution, there is 5.33mol of sulphuric acid

Molarity= moles/ volume in litre

=5.33/1

=5.33M

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Most popular questions from this chapter

Question- Determine the empirical formula for the compounds with the following percentage composition:

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