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Chapter 17: Q17.2E (page 957)

For the scenario in the previous question, how many electrons moved through the circuit.

Short Answer

Expert verified

Number of electrons is \({\rm{3}}{\rm{.28 \times 1}}{{\rm{0}}^{{\rm{22}}}}\)

Step by step solution

01

Formula of number of electron

The charge of 1 electron is equal to\({\bf{1}}{\bf{.6022 \times 1}}{{\bf{0}}^{{\bf{ - 19}}}}{\bf{C}}\). Thus, in 1C, the number of electrons will be:

\(\begin{array}{l}{\bf{1C = }}\frac{{\bf{1}}}{{{\bf{1}}{\bf{.6022 \times 1}}{{\bf{0}}^{{\bf{ - 19}}}}}}{\bf{ }}\\{\bf{electrons = 6}}{\bf{.2414 \times 1}}{{\bf{0}}^{{\bf{18}}}}{\bf{ electrons}}\end{array}\)

02

Determine the number of electrons

For 5250 C of charge, the number of electrons can be calculated as follows:

\({\rm{1C}} \to {\rm{6}}{\rm{.2414 \times 1}}{{\rm{0}}^{{\rm{18}}}}{\rm{ electrons }}\)

Thus, \(5250{\rm{C}} \to (5250)\left( {6.2414 \times {{10}^{18}}{\rm{ electrons }}} \right) = 3.28 \times {10^{22}}{\rm{ electrons }}\)

Therefore, the number of electrons are \(3.28 \times 1{0^{22}}\).

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Most popular questions from this chapter

List some things that are typically considered when selecting a battery for a new application.

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For each reaction listed, determine its standard cell potential at \({25\circ }{\rm{C}}\) and whether the reaction is spontaneous at standard conditions.

(a)\({\mathop{\rm Mn}\nolimits} (s) + {\rm{N}}{{\rm{i}}^{2 + }}(aq) \to {{\mathop{\rm Mn}\nolimits} ^{2 + }}(aq) + {\rm{Ni}}(s)\)

(b)\(3{\rm{C}}{{\rm{u}}^{2 + }}(aq) + 2{\rm{Al}}(s) \to 2{\rm{A}}{{\rm{l}}^{3 + }}(aq) + 3{\rm{Cu}}(s)\)

(c)\({\rm{Na}}(s) + {\rm{LiN}}{{\rm{O}}_3}(aq) \to {\rm{NaN}}{{\rm{O}}_3}(aq) + {\rm{Li}}(s)\)

(d) \({\rm{Ca}}{\left( {{\rm{N}}{{\rm{O}}_3}} \right)_2}(aq) + {\rm{Ba}}(s) \to {\rm{Ba}}{\left( {{\rm{N}}{{\rm{O}}_3}} \right)_2}(aq) + {\rm{Ca}}(s)\)
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