An active (metal) electrode was found to lose mass as the oxidation-reduction reaction was allowed to proceed. Was the electrode part of the anode or cathode? Explain.

Short Answer

Expert verified

The active electrode that loses mass is the part of anode.

Step by step solution

01

Define oxidation and reduction

  • Avoltaic or a galvaniccell is an electrochemical cell which derives the electrical energy from the spontaneous redox chemical reactions which occur inside the cell.
  • A galvanic cell usually contains two different metals which are dipped in an electrolytic solution or of an individual half-cells having different metals and their ions present in the solution, joined by a salt-bridge or divided by a porous membrane.
02

Determine balanced reaction for each pair of half reactions in an acidic solution.  

Active electrodes are those electrodes in which the mass are found to be changes as the chemical reaction proceeds in the electrolyte solution.

When the electricity is pass through a solution of an electrolyte, chemical reaction occurs at the electrodes. The electrode connected to negative terminal of battery is termed as cathode whereas that connected to positive terminal of battery is termed as anode. At anode, oxidation of metal atoms takes place and they move into the solution. Therefor the active electrode that loses mass is the part of the anode.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What mass of each product is produced in each of the electrolytic cells of the previous problem if a total charge of \({\bf{3}}.{\bf{33}} \times {\bf{1}}{{\bf{0}}^5}{\rm{ }}{\bf{C}}\) passes through each cell? Assume the voltage is sufficient to perform the reduction

Aluminium\(\left( {{\bf{E}}_{{\bf{A}}{{\bf{l}}^{{\bf{3 + }}}}{\bf{/Al}}}^{\bf{^\circ }}{\bf{ = - 2}}{\bf{.07\;V}}} \right)\) is more easily oxidized than iron \(\left( {{\bf{E}}_{{\bf{F}}{{\bf{e}}^{\bf{3}}}}^{\bf{^\circ }}{\bf{/F}}{{\bf{e}}^{\bf{ - }}}{\bf{ = - 0}}{\bf{.477\;V}}} \right){\bf{,}}\) and yet when both are exposed to the environment, untreated aluminium has very good corrosion resistance while the corrosion resistance of untreated iron is poor. Explain this observation.

Determine the overall reaction and its standard cell potential at \({25\circ }{\rm{C}}\) for these reactions. Is the reaction spontaneous at standard conditions? Assume the standard reduction for \({\rm{B}}{{\rm{r}}_2}(l)\) is the same as for \({\rm{B}}{{\rm{r}}_2}(aq)\).

The mass of three different metal electrodes, each from a different galvanic cell, were determined before andafter the current generated by the oxidation-reduction reaction in each cell was allowed to flow for a few minutes.The first metal electrode, given the label A, was found to have increased in mass; the second metal electrode, giventhe label B, did not change in mass; and the third metal electrode, given the label C, was found to have lost mass.

Make an educated guess as to which electrodes were active and which were inert electrodes, and which wereanode(s) and which were the cathode(s)

Balance the following in basic solution:

(a) \({\bf{S}}{{\bf{O}}_{\bf{3}}}^{{\bf{2 - }}}{\bf{(aq) + Cu(OH}}{{\bf{)}}_{\bf{2}}}{\bf{(s)}} \to {\bf{S}}{{\bf{O}}_{\bf{4}}}^{{\bf{2 - }}}{\bf{(aq) + Cu(OH)(s)}}\)

(b) \({{\bf{O}}_{\bf{2}}}{\bf{(g) + Mn(OH}}{{\bf{)}}_{\bf{2}}}{\bf{(s)}} \to {\bf{Mn}}{{\bf{O}}_{\bf{2}}}{\bf{(s)}}\)

(c) \({\bf{N}}{{\bf{O}}_{\bf{3}}}^{\bf{ - }}{\bf{(aq) + }}{{\bf{H}}_{\bf{2}}}{\bf{(g)}} \to {\bf{NO(g)}}\)

(d) \({\bf{Al(s) + Cr}}{{\bf{O}}_{\bf{4}}}^{{\bf{2 - }}}{\bf{(aq)}} \to {\bf{Al(OH}}{{\bf{)}}_{\bf{3}}}{\bf{(s) + Cr(OH}}{{\bf{)}}_{\bf{4}}}^{\bf{ - }}{\bf{(aq)}}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free