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Chapter 15: Q46E (page 874)

Question: A solution contains \(1.0 \times 1{0^{ - 5}}\)mol of KBr and 0.10 mol of KCl per liter. \(AgN{O_3}\)is gradually added to this solution. Which forms first, solid AgBr or solid AgCl?

Short Answer

Expert verified

The Solid AgCl will form first.

Step by step solution

01

Find which will form first:

For AgCl,

\(\begin{array}{*{20}{c}}{{K_{sp}}(AgCl) = \left( {A{g^ + }} \right)\left( {C{l^ - }} \right) = 1.8 \times {{10}^{ - 10}}}\\{\left( {A{g^ + }} \right) = \frac{{1.8 \times {{10}^{ - 10}}}}{{0.10M}} = 1.8 \times {{10}^{ - 9}}M}\end{array}\)

For AgBr,

\(\begin{array}{*{20}{c}}{{K_{sp}}(AgBr) = \left( {A{g^ + }} \right)\left( {B{r^ - }} \right) = 5.4 \times {{10}^{ - 13}}}\\{\left( {A{g^ + }} \right) = \frac{{5.4 \times {{10}^{ - 13}}}}{{1 \times {{10}^{ - 5}}M}} = 5.4 \times {{10}^{ - 8}}M}\end{array}\)

\(\left( {A{g^ + }} \right)(AgCl) < \left( {A{g^ + }} \right)(AgBr)\)

Therefore the solution is solid AgCl will form first.

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Most popular questions from this chapter

Question: Using Lewis structures, write balanced equations for the following reactions:

\({\rm{\;}}(a)\;HCl(g) + P{H_3}(g) \to \)

\({\rm{\;}}(b)\;{H_3}{O^ + } + CH_3^ - \to \)

\({\rm{\;}}(c)\;CaO + S{O_3} \to \)

\(\;(d)\;NH_4^ + + {C_2}{H_5}{O^ - } \to \)

Question: Calculate the equilibrium concentration of Zn2+ in a 3.0 M solution of\(Zn(CN)_4^{2 - }\) .

What is the molar solubility of BaSO4 in a 0.250-M solution of NaHSO4? Ka for HSO4 − = 1.2×10–2.

What is the effect on the amount of\(CaHP{O_4}\) that dissolves and the concentrations of \(C{a^{2 + }}\;and\;HPO_4^ - \)when each of the following are added to a mixture of solid \(CaHP{O_4}\)and water at equilibrium?

\(\;(a)\;CaC{l_2}\)

\(\;(b)\;HCl\)

\(\;(c)\;KCl{O_4}\)

\(\;(d)\;NaOH\)

\(\;(e)\;CaHP{O_4}\)

Question: 30. Which of the following compounds precipitates from a solution that has the concentrations indicated? (See Appendix J for \({K_{sp}}\) values.)

(a) \(KCl{O_4}:\left( {{K^ + }} \right) = 0.01{M^ - }\left( {ClO_4^ - } \right) = 0.01M\)

(b) \({K_2}PtC{l_6}:\left( {{K^ + }} \right) = 0.01M,\left( {PtC{l_6}^{2 - }} \right) = 0.01M\) \(\)

(c) \(Pb{I_2}:\left( {P{b^{2 + }}} \right) = 0.003M,\left( {{I^ - }} \right) = 1.3 \times 1{0^{ - 3}}M\)

(d) \(A{g_2}\;S:\left( {A{g^ + }} \right) = 1 \times 1{0^{ - 10}}M,\left( {{S^{2 - }}} \right) = 1 \times 1{0^{ - 13}}M\)

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