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Chapter 1: Q1E (page 54)

Explain how you could experimentally determine whether the outside temperature is higher or lower than 0 °C (32 °F) without using a thermometer.

Short Answer

Expert verified

We can determine the temperature by performing a simple experiment with a glass of water. If the water in the glass freezes at the temperature in the room, we can conclude that the temperature is below 0 °C (32 °F). The temperature at which water freezes is 0 °C (32 °F). 0 °C (32 °F) is the freezing point of water. If the water doesn’t freeze, then the temperature is not 0 °C (32 °F) or less.

Step by step solution

01

Experimental evaluation:

Let’s take 2 glasses and name them A and B. Now fill A with room temperature water and glass B with freezing water. And place them in the room for evaluation.

02

Temperature determination:

Now, if the water in glass A starts to freeze and the water in glass B does not show any change, then the temperature is 0 °C (32 °F) or less. If the water in glass A does not freeze and the water in glass B starts to melt, the temperature is more than 0 °C (32 °F).

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Most popular questions from this chapter

Question: Make the conversion indicated in each of the following:

(a) the length of a soccer field, 120 m (three significant figures), to feet

(b) the height of Mt. Kilimanjaro, at 19,565 ft the highest mountain in Africa, to kilometers

(c) the area of an 8.5 × 11-inch sheet of paper in cm2

(d) the displacement volume of an automobile engine, 161 in.3, to liters

(e) the estimated mass of the atmosphere, 5.6 × 1015 tons, to kilograms

(f) the mass of a bushel of rye, 32.0 lb, to kilograms

(g) the mass of a 5.00-grain aspirin tablet to milligrams (1 grain = 0.00229 oz)

The following quantities were reported on the labels of commercial products. Determine the number of significant figures in each.

(a) 0.0055 g active ingredients

(b) 12 tablets

(c) 3% hydrogen peroxide

(d) 5.5 ounces

(e) 473 mL

(f) 1.75% bismuth

(g) 0.001% phosphoric acid

(h) 99.80% inert ingredients

Convert the boiling temperature of liquid ammonia, \( - 28.1^\circ F,\) into degrees Celsius and kelvin.

Both graphite and diamond burn.

\({\bf{C}}\left( {{\bf{s, diamond}}} \right){\bf{ + }}{{\bf{O}}_{\bf{2}}}\left( {\bf{g}} \right) \to {\bf{C}}{{\bf{O}}_{\bf{2}}}\left( {\bf{g}} \right)\)

For the conversion of graphite to diamond:

\({\bf{C}}\left( {{\bf{s, graphite}}} \right) \to {\bf{C}}\left( {{\bf{s, diamond}}} \right){\bf{ \Delta {\rm H}}}_{{\bf{298}}}^{\bf{^\circ }}{\bf{ = 1}}{\bf{.90 kJ}}\)

Which produces more heat, the combustion of graphite or the combustion of a diamond?

The label on a pressurized can of spray disinfectant warns against heating the can above \(130^\circ F\)). What are the corresponding temperatures on the Celsius and kelvin temperature scales?
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