Question: A chemist’s 50-Trillion Angstrom Run (see Exercise 1.78) would be an archeologist’s 10,900 cubit run. Howlong is one cubit in meters and in feet? (1 Å = 1 × 10-8 cm)

Short Answer

Expert verified

One cubit is 0.46 m and 1.5 ft long.

Step by step solution

01

Defining the Trillion Angstrom and cubit units

We know that one trillion Angstrom is equal to 5 km (from Exercise 1.78).

A cubit is an ancient measure unit. It is measured based on the length between the elbow to the middle finger.

Also, 10,900 cubits are considered 50 Trillion Angstrom.

02

Converting the cubit into meters and feet

We know that

\(\begin{array}{c}50\,\,trillion\,Angstrom\,\, = \,\,\,50\,\, \times \,\,{10^{12}}\, \times \,{10^{ - 10}}\,m\,\\\, = \,\,5000\,\,m\\\,\, = \,\,5\,\,km\end{array}\)

And

\(10,900\,\,cubit\,\, = \,\,\,50\,trillion\,\,Angstrom\)

Therefore,

\(10,900\,\,cubit\,\, = \,\,5000\,\,m\)

\(\begin{array}{l}1\,\,cubit\,\, = \,\,\frac{{5000}}{{10,900}}\,\,m\,\,\\1\,\,cubit\,\, = \,\,\,0.4587\,\,m\end{array}\)

Rounding off, we get 0.46 m.

Also, we know

\(1\,\,m\,\, = \,\,3.28\,\,ft\)

We get

\(\begin{array}{c}1\,\,cubit\,\, = \,\,0.4587\,\,m\,\\\, = \,\,1.5049\,\,ft\end{array}\)

Rounding off, we get 1.5 ft.

Therefore, one cubit in meters and feet are 0.46 m and 1.5 ft.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free