Question:Calculate the value of the equilibrium constant \({K_P}\) for the reaction \(2NO(g) + C{l_2}(g) \rightleftharpoons 2NOCl(g)\) from these equilibrium pressures: NO, \(0.050atm;C{l_2},0.30atm;NOCl,1.2atm\)

Short Answer

Expert verified

Thevalue of equilibrium constant\(K = 1920\)

Step by step solution

01

Define Equilibrium

Equilibrium is the state in which market supply and demand balance each other, and as a result prices become stable

02

Calculating the Equilibrium constant

We need to calculate equilibrium pressure constant for following reaction

\(2NO(g) + C{l_2}(g) \rightleftharpoons 2NOCl(g)\])

this is a reverse reaction so it should be written with a double arrow. Equilibrium constant is calculated like this:

\({K_p} = \frac{{p(NOCl)_{eq}^2}}{{p{{\left( {C{l_2}} \right)}_{eq}} \cdot p(NO)_{eq}^2}}\)

03

The pressure of the compound \({p_{eq}}\)

Theis pressure of the compound in the equilibrium. We are given all the data in the task:

\(\begin{array}{*{20}{c}}{p{{(NOCl)}_{eq}} = 1.2{\rm{atm}}}\\{p{{\left( {C{l_2}} \right)}_{eq}} = 0.30{\rm{atm}}}\\{p{{(NO)}_{eq}} = 0.050{\rm{atm}}}\end{array}\)

We calculate\(\begin{array}{*{20}{c}}{{K_p} = \frac{{{{1.2}^2}}}{{0.30 \cdot {{0.050}^2}}}}\\{K = 1920}\end{array}\)

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Most popular questions from this chapter

How can the pressure of water vapor are increased in the following equilibrium?

\({H_2}O(l) \rightleftharpoons {H_2}O(g)\) \(\Delta H = 41kJ\)

What is the pressure of \(BrCl\) in an equilibrium mixture of \(C{l_2}\), \(B{r_2}\), and \(BrCl\) if the pressure of \(C{l_2}\) in the mixture is \(0.115atm\)and the pressure of \(B{r_2}\) in the mixture is \(0.450atm\)?

\(C{l_2}(g) + B{r_2}(g) \rightleftharpoons 2BrCl(g)\)

\({K_P} = 4.7 \times 1{0^{ - 2}}\)

A necessary step in the manufacture of sulfuric acid is the formation of sulfur trioxide (\({\rm{S}}{{\rm{O}}_3}\)), from sulfur dioxide (\({\rm{S}}{{\rm{O}}_2}\)), and oxygen (\({{\rm{O}}_2}\)), shown here.

\(2{\text{S}}{{\text{O}}_2}(g) + {{\text{O}}_2}(g) \rightleftharpoons 2{\text{S}}{{\text{O}}_3}(g)\)

At high temperatures, the rate of formation of \({\rm{S}}{{\rm{O}}_3}\)is higher, but the equilibrium amount (concentration or partial pressure) of \({\rm{S}}{{\rm{O}}_3}\) is lower than it would be at lower temperatures.

(a) Does the equilibrium constant for the reaction increase, decrease, or remain about the same as the temperature increases?

(b) Is the reaction endothermic or exothermic?

Calculate the pressures of all species at equilibrium in a mixture of NOCl, NO, and Cl2produced when a sample of NOCl with a pressure of 10.0 atm comes to equilibrium according to this reaction:

\(2NOCl(g) \rightleftharpoons 2NO(g) + C{l_2}(g)\quad {K_P} = 4.0 \times 1{0^{ - 4}}\)

A student solved the following problem and found \(\left[ {{N_2}{O_4}} \right] = 0.16M\)at equilibrium. How could this student recognize that the answer was wrong without reworking the problem? The problem was: What is the equilibrium concentration of \(\left[ {{N_2}{O_4}} \right]\) in a mixture formed from a sample of \(N{O_2}\) with a concentration of \(0.10M\)?

\(2N{O_2}(g) \rightleftharpoons {N_2}{O_4}(g)\)

\({K_c} = 160\)

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