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Chapter 13: Q64E (page 758)

Why are there no changes specified for NH4HS? What property of Ni does change?

Short Answer

Expert verified

Pure solids (or liquids) are excluded from the equilibrium expression because their effective concentrations stay constant throughout the reaction.

Since,NH4HSis solid, there will be no change in concentration

But the property ofNH4HS(s) that does change is its mass

Step by step solution

01

Properties of sodium

  • Sodium has a strong metallic luster and in color is very analogous to silver.
  • It is soft at common temperatures that it may be formed into leaves by the pressure of the fingers.
  • Sodium compounds soon tarnish on exposure to the air, though less rapidly than potassium.
  • Sodium is instantly oxidized by water, and hydrogen gas in temporary union with a little sodium being disengaged.
02

Reason for no changes

Pure solids (or liquids) are excluded from the equilibrium expression because their effective concentrations stay constant throughout the reaction.

sinceNH4HS is solid, there will be no change in concentration.

But the property ofNH4HS (S) that does change is its mass.

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Most popular questions from this chapter

The following equation represents a reversible decomposition:

\({\mathbf{CaC}}{{\mathbf{O}}_3}{\text{ }}\left( {\mathbf{s}} \right) \rightleftharpoons {\mathbf{CaO}}\left( {\mathbf{s}} \right){\text{ }} + {\text{ }}{\mathbf{C}}{{\mathbf{O}}_2}{\text{ }}\left( {\mathbf{g}} \right):\)

Under what conditions will decomposition in a closed container proceed to completion so that no \({\bf{CaC}}{{\bf{O}}_3}\) remains?

Benzene is one of the compounds used as octane enhancers in unleaded gasoline. It is manufactured by the catalytic conversion of acetylene to benzene: \(3{{\rm{C}}_2}{{\rm{H}}_2}(g) \to {{\rm{C}}_6}{{\rm{H}}_6}(g)\). Which value of \({K_c}\) would make this reaction most useful commercially?

\({K_c} \approx 0.01,\;{K_c} \approx 1,\;\;{\rm{or}}\;{K_c} \approx 10.\) Explain your answer.

Write the expression of the reaction quotient for the ionization of HOCN in water.

Assume that the change in pressure of \({H_2}S\) is small enough to be neglected in the following problem.(a) Calculate the equilibrium pressures of all species in an equilibrium mixture that results from the decomposition of H2S with an initial pressure of 0.824 atm.

\(2{H_2}S(g) \rightleftharpoons 2{H_2}(g) + {S_2}(g)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{K_p} = 2.2 \times {10^{( - 6)}}\)

(b) Show that the change is small enough to be neglected.

Calculate the pressures of all species at equilibrium in a mixture of NOCl, NO, and Cl2produced when a sample of NOCl with a pressure of 10.0 atm comes to equilibrium according to this reaction:

\(2NOCl(g) \rightleftharpoons 2NO(g) + C{l_2}(g)\quad {K_P} = 4.0 \times 1{0^{ - 4}}\)
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