The pressure of a sample of gas is measured at sea level with an open-end mercury manometer. Assuming atmospheric pressure is 760.0mm Hg ,determine the pressure of the gas in: (a) mm Hg (b) (c) kPa.

The force applied perpendicular to an object's surface per unit area across which that force is spread is known as pressure.

In the given scenario, we have an open- end manometer

P_x = pressure of gas

P_y = h + P₀

P_gas= P₀+ h

P₀= Atmosphereic pressure

P_gas = gas pressure

a) Converting cmto Hg pressure into mm of Hg

1cm of Hg = 10mm of Hg

26.4 cm of Hg = (26.4) × (10) mm of Hg

= 264 mm of Hg

P₀ = 760 mm of Hg

h = 264 mm of Hg

P_gas = (P₀ + h)

= (760 + 264) mm of Hg

= 1024 mm of Hg

Therefore, the Pressure is 1024 mm of Hg

Converting mm of Hg pressure into atm

1mm of Hg = 0.001315 atm

1024 mm of Hg = (1024) ×(0.001315) atm

= 1.35atm

Therefore, the Pressure is 1.35 atm

Converting mm of Hg pressure into kPa

1mm of Hg = 0.001333kPa

1024 mm of Hg = (1024) ×(0.1333) kPa

= 136.5 kPa

Therefore, the Pressure is 136.5 kPa