Under certain conditions, the decomposition of ammonia on a metal surface gives the following data:

Determine the rate law, the rate constant, and the overall order for this reaction.

Short Answer

Expert verified

The rate law for decomposition of ammonia is equal to the rate constant. The value of rate law and rate constant is \({\bf{1}}{\bf{.5 \times 1}}{{\bf{0}}^{{\bf{ - 6}}}}{\bf{mol/L/h}}\)

The overall order of the reaction is zero.

Step by step solution

01

Decomposition of ammonia on a metal surface

From the given table, it is clear that the rate of reaction is independent of the concentration of reactant which is the condition of zero order reaction.

Hence, decomposition of ammonia on a metal surface is a zero-order reaction. The gas is absorbed on the metal surface due to pressure.

02

Rate law and rate constant

The rate law for a zero-order reaction is as follows:

\({\bf{Rate = k}}\)

Where k is a rate constant.

So, for decomposition of ammonia rate law will be equal the rate constant and does not depend on the concentration of reactant.

Value of rate constant\({\bf{k = 1}}{\bf{.5 \times 1}}{{\bf{0}}^{{\bf{ - 6}}}}{\bf{mol/L/h}}\)

Rate law\({\bf{ = k = 1}}{\bf{.5 \times 1}}{{\bf{0}}^{{\bf{ - 6}}}}{\bf{mol/L/h}}\)

Hence, the overall rate of reaction will be zero.

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Most popular questions from this chapter

Nitro-glycerine is an extremely sensitive explosive. In a series of carefully controlled experiments, samples of the explosive were heated to 160 °C, and their first-order decomposition was studied. Determine the average rate constants for each experiment using the following data:

Initial (\({{\bf{C}}_{\bf{3}}}{{\bf{H}}_{\bf{5}}}{{\bf{N}}_{\bf{3}}}{{\bf{O}}_{\bf{9}}}\)) (M)

4.88

3.52

2.29

1.81

5.33

4.05

2.95

1.72

t(s)

300

300

300

300

180

180

180

180

% Decomposed

52.0

52.9

53.2

53.9

34.6

35.9

36.0

35.4

For the reaction\({\bf{Q}} \to {\bf{W + X}}\), the following data were obtained at 30 °C

  1. What is the order of the reaction with respect to (Q), and what is the rate law?
  2. What is the rate constant?

The rate constant at 325°C for the decomposition reaction \({{\bf{C}}_{\bf{4}}}{{\bf{H}}_{\bf{8}}} \to {\bf{2}}{{\bf{C}}_{\bf{2}}}{{\bf{H}}_{\bf{4}}}\)is 6.1 × 10−8 s−1, and the activation energy is 261 kJ per mole of\({{\bf{C}}_{\bf{4}}}{{\bf{H}}_{\bf{8}}}\). Determine the frequency factor for the reaction.

Pure ozone decomposes slowly to oxygen,\({\bf{2}}{{\bf{O}}_{\bf{3}}}{\bf{(g)}} \to {\bf{3}}{{\bf{O}}_{\bf{2}}}{\bf{(g)}}\). Use the data provided in a graphical method and determine the order and rate constant of the reaction.

Time(hr)

0

2.0x103

7.6x 104

1.00x104

1.23x104

1.43x104

1.70x104

(O3) (M)

1.0x10-5

4.98x10-6

2.07x10-6

1.66x10-6

1.39x10-6

1.22x10-6

1.05x10-6

What is the half-life for the first-order decay of carbon-14?

\({{\bf{\;}}_{\bf{6}}}^{{\bf{14}}}{\bf{C}}\)⟶\({_{\bf{7}}^{{\bf{14}}}}{\bf{N + }}{{\bf{e}}^{\bf{ - }}}\)

The rate constant for the decay is\({\bf{1}}{\bf{.21 \times 1}}{{\bf{0}}^{{\bf{ - 4}}}}{\bf{yea}}{{\bf{r}}^{{\bf{ - 1}}}}\).

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