What is the rate equation for the elementary termolecular reaction A + 2B⟶products? For 3A⟶products?

Short Answer

Expert verified

For any reaction, the rate is given by the product of the concentration of the reactant, where each reactant concentration is raised to the power of the stoichiometric ratio.

Step by step solution

01

Termolecular reaction

For elementary termolecular reaction \({\bf{A + 2B}} \to {\bf{products}}\).

\({\bf{Rate = }}\left( {\bf{A}} \right){\left( {\bf{B}} \right)^{\bf{2}}}\).

Each concentration term in the rate equation is raised to the power equivalent to the stoichiometry of the particular reactant.

02

Rate of Termolecular reaction involving same reactants

For elementary reaction \({\bf{3A}} \to {\bf{products}}\), the rate of reaction is given by

\({\bf{Rate = }}{\left( {\bf{A}} \right)^{\bf{3}}}\)

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Most popular questions from this chapter

There are two molecules with the formula\({{\bf{C}}_{\bf{3}}}{{\bf{H}}_{\bf{6}}}\). Propene,\({\bf{C}}{{\bf{H}}_{\bf{3}}}{\bf{CH = C}}{{\bf{H}}_{\bf{2}}}\), is the monomer of the polymer polypropylene, which is used for indoor-outdoor carpets. Cyclopropane is used as an anaesthetic:

When heated to 499\({\bf{^\circ C}}\), cyclopropane rearranges (isomerizes) and forms propene with a rate constant of\({\bf{5}}{\bf{.95 \times 1}}{{\bf{0}}^{{\bf{ - 4}}}}{{\bf{s}}^{{\bf{ - 1}}}}\). What is the half-life of this reaction? What fraction of the cyclopropane remains after 0.75 h at 499.5\({\bf{^\circ C}}\)?

Under certain conditions, the decomposition of ammonia on a metal surface gives the following data:

Determine the rate law, the rate constant, and the overall order for this reaction.

For the reaction\({\bf{A}} \to {\bf{B + C}}\), the following data were obtained at 30 °C:

  1. What is the order of the reaction with respect to (A), and what is the rate law?
  2. What is the rate constant?

Consider this scenario and answer the following questions: Chlorine atoms resulting from decomposition of chlorofluoromethanes, such as \({\bf{CC}}{{\bf{l}}_{\bf{2}}}{{\bf{F}}_{\bf{2}}}\), catalyse the decomposition of ozone in the atmosphere. One simplified mechanism for the decomposition is:

\(\begin{aligned}{}{{\bf{O}}_{\bf{3}}}\overset{sunlight}{\rightarrow}{}{{\bf{O}}_{\bf{2}}}{\rm{ }} + {\rm{ }}{\bf{O}}\\{{\bf{O}}_{\bf{3}}}{\rm{ }} + {\rm{ }}{\bf{Cl}}\to {{\bf{O}}_{\bf{2}}}{\rm{ }} + {\rm{ }}{\bf{ClO}}\\{\bf{ClO}}{\rm{ }} + {\rm{ }}{\bf{O}}\to {\bf{Cl}}{\rm{ }} + {\rm{ }}{{\bf{O}}_{\bf{2}}}\end{aligned}\)

(a) Explain why chlorine atoms are catalysts in the gas-phase transformation:

\({\bf{2}}{{\bf{O}}_{\bf{3}}}\mathop {}\limits^{}\to {\bf{3}}{{\bf{O}}_{\bf{2}}}\)

(b) Nitric oxide is also involved in the decomposition of ozone by the mechanism: Is NO a catalyst for the decomposition? Explain your answer.

\(\begin{aligned}{}{{\bf{O}}_{\bf{3}}}\overset{sunlight}{\rightarrow}{\rm{ }}{{\bf{O}}_{\bf{2}}}{\rm{ }} + {\rm{ }}{\bf{O}}\\{{\bf{O}}_{\bf{3}}}{\rm{ }} + {\rm{ }}{\bf{NO}}\rightarrow {\bf{N}}{{\bf{O}}_{\bf{2}}}{\rm{ }} + {\rm{ }}{{\bf{O}}_{\bf{2}}}\\{\bf{N}}{{\bf{O}}_{\bf{2}}}{\rm{ }} + {\rm{ }}{\bf{O}}\rightarrow {\bf{NO}}{\rm{ }} + {\rm{ }}{{\bf{O}}_{\bf{2}}}\end{aligned}\)

A study of the rate of the reaction represented as 2A⟶ B gave the following data:

  1. Determine the average rate of disappearance of A between 0.0 s and 10.0 s, and between 10.0 s and 20.0 s.
  2. Estimate the instantaneous rate of disappearance of A at 15.0 s from a graph of time versus (A). What are the units of this rate?
  3. Use the rates found in parts (a) and (b) to determine the average rate of formation of B between 0.00 s and 10.0 s, and the instantaneous rate of formation of B at 15.0 s.
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