Ethane \(\left( {{\rm{C}}{{\rm{H}}_3}{\rm{C}}{{\rm{H}}_3}} \right)\) has a melting point of -1830C and a boiling point of -890C. Predict the melting and boiling points for methylamine \(\left( {{\rm{C}}{{\rm{H}}_3}{\rm{N}}{{\rm{H}}_2}} \right)\). Explain your reasoning.

Short Answer

Expert verified

Ethane is a non-polar molecule, therefore, only weak van der waals force of attraction are present.

Step by step solution

01

Define polarizability

A molecule that has a charge cloud that is easily distorted is said to be very polarizable and will have large dispersion forces; one with a charge cloud that is difficult to distort is not very polarizable and will have small dispersion forces.

02

 Identify the melting and boiling point of methylamine

Both the melting point and boiling point of methylamine will be more than that of ethane as hydrogen bonds are present in its molecules Therefore, more energy is required to break the bonds and hence, the melting and boiling point will be more. On the other hand, ethane is a non-polar molecule, therefore, only weak van der waals force of attraction are present.

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Most popular questions from this chapter

Which contains the compounds listed correctly in order of increasing boiling points

\(\begin{aligned}{\rm{(a)}}{{\rm{N}}_{\rm{2}}}{\rm{ < C}}{{\rm{S}}_{\rm{2}}}{\rm{ < }}{{\rm{H}}_{\rm{2}}}{\rm{O < KCl}}\\{\rm{(b)}}{{\rm{H}}_{\rm{2}}}{\rm{O < }}{{\rm{N}}_{\rm{2}}}{\rm{ < C}}{{\rm{S}}_{\rm{2}}}{\rm{ < KCl}}\\{\rm{(c)}}{{\rm{N}}_{\rm{2}}}{\rm{ < KCl < C}}{{\rm{S}}_{\rm{2}}}{\rm{ < }}{{\rm{H}}_{\rm{2}}}{\rm{O}}\\{\rm{(d)C}}{{\rm{S}}_{\rm{2}}}{\rm{ < }}{{\rm{N}}_{\rm{2}}}{\rm{ < KCl < }}{{\rm{H}}_{\rm{2}}}{\rm{O}}\\{\rm{(e)KCl < }}{{\rm{H}}_{\rm{2}}}{\rm{O < C}}{{\rm{S}}_{\rm{2}}}{\rm{ < }}{{\rm{N}}_{\rm{2}}}\end{aligned}\)

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Open the PhET States of Matter Simulation (http://openstaxcollege.org/l/16phetvisual) to answer the following questions:

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