Question: In terms of the kinetic molecular theory, in what ways are liquids similar to gases? In what ways are liquids different from gases?

Short Answer

Expert verified

Yes, both liquids and gases are similar as well as different according to the kinetic molecular theory.

Step by step solution

01

Definition of Gases

A gas is a sample of a matter that conforms to the shape of a container in which it is contained, and achieves a consistent density inside the container, even in the presence of gravity, regardless of the amount of substance in the container.

If a gaseous substance, commonly referred to as a vapour, is not contained, it will disperse into space. The term "gas" can also refer to a substance's state or condition when it has this property.

02

Step 2: Determine the similarities between liquids and gases

Liquids and gases are similar in the way that both liquids, as well as gas particles, are free to move from one position to another.

03

Step 3: Determine the differences between liquid and gases

The distinction between liquids and gases is that the liquid particles are constrained by the geometry of a container in which they are maintained, but the gas particles expand infinitely.

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Consider a cylinder containing a mixture of liquid carbon dioxide in equilibrium with gaseous carbon dioxide at an initial pressure of \({\rm{65}}\) atm and a temperature of \({\rm{2}}{{\rm{0}}^{\rm{o}}}{\rm{C}}\). Sketch a plot depicting the change in the cylinder pressure with time as gaseous carbon dioxide is released at constant temperature.

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\(\begin{aligned}{\rm{(a)}}\,{\rm{3}}{{\rm{5}}^{\rm{^\circ }}}{\rm{C}}\,{\rm{and}}\,{\rm{85}}\,{\rm{kPa}}\\{\rm{(b) - 1}}{{\rm{5}}^{\rm{^\circ }}}{\rm{C}}\,{\rm{and}}\,{\rm{40}}\,{\rm{kPa}}\\{\rm{(c) - 1}}{{\rm{5}}^{\rm{^\circ }}}{\rm{C}}\,{\rm{and}}\,{\rm{0}}{\rm{.1}}\,{\rm{kPa}}\\{\rm{(d)7}}{{\rm{5}}^{\rm{^\circ }}}{\rm{C}}\,{\rm{and}}\,{\rm{3}}\,{\rm{kPa}}\\{\rm{(e)4}}{{\rm{0}}^{\rm{^\circ }}}{\rm{C}}\,{\rm{and}}\,{\rm{0}}{\rm{.1}}\,{\rm{kPa}}\\{\rm{(f)6}}{{\rm{0}}^{\rm{^\circ }}}{\rm{C}}\,{\rm{and}}\,{\rm{50}}\,{\rm{kPa}}\end{aligned}\)

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