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Chapter 18: Q79E (page 1046)

Predict the product of burning francium in air.

Short Answer

Expert verified

Francium oxide is produced when francium is burned in air.

Step by step solution

01

Details of francium

  • In the periodic table, francium (Fr) belongs to group IA. It's a valence electron configuration alkali metal having a valence electron configuration of\(7\;{{\rm{s}}^1}\)
  • Alkali metals are highly electropositive, which means they readily lose valence electrons, making them reactive.
02

Reaction of francium when burning

Then burned, francium rapidly interacts with oxygen to produce francium oxide. The following is a representation of the reaction:

\(4{\rm{Fr}} + {{\rm{O}}_2} \to 2{\rm{F}}{{\rm{r}}_2}{\rm{O}}\)

Therefore, francium oxide is produced when francium is burned in air.

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Most popular questions from this chapter

Write an equation for the reduction of cesium chloride by elemental calcium at high temperature.

Write balanced chemical equations for the following reactions:

(a) cadmium burned in air

(b) elemental cadmium added to a solution of hydrochloric acid

(c) cadmium hydroxide added to a solution of acetic acid, \({\rm{C}}{{\rm{H}}_3}{\rm{C}}{{\rm{O}}_2}{\rm{H}}\)

What is the oxidation state of the nobel gas in each of the following ?

(a) \({\rm{Xe}}{{\rm{O}}_{\rm{2}}}{{\rm{F}}_2}\) (b) \({\rm{Kr}}{{\rm{F}}_{\rm{2}}}\) (c) \({\rm{XeF}}_{\rm{3}}^{\rm{ + }}\) (d) \(\)\({\rm{XeO}}_{\rm{6}}^{{\rm{4 - }}}\)

Which is the stronger acid,\({{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}\)or \({{\rm{H}}_2}{\rm{Se}}{{\rm{O}}_4}\)? Why? You may wish to review the chapter on acid-base equilibrium.

Give the hybridization of xenon in each of the following. You may wish to review the chapter on the advanced theories of covalent bonding.

\(\begin{array}{l}(a){\rm{Xe}}{{\rm{F}}_2}\\(b){\rm{Xe}}{{\rm{F}}_4}\\(c){\rm{Xe}}{{\rm{O}}_3}\\(d){\rm{Xe}}{{\rm{O}}_4}\\(e){\rm{XeO}}{{\rm{F}}_4}\end{array}\)
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