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Mobile App Chapter 18: Q91 E (page 1047)
Give the hybridization and oxidation state for sulfur in\({\rm{S}}{{\rm{O}}_2}\), in\({\rm{S}}{{\rm{O}}_3}\), and in\({{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}\).
Short Answer
Therefore,
- The oxidation number of is\( + 4\).
- The oxidation number of\({\rm{S}}{{\rm{O}}_3}\)is\( + 6\).
- The oxidation number of \({{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}\)is \( + 6\).
Step by step solution
What is the oxidation state of \({\rm{S}}{{\rm{O}}_2}\).
a) In\({\rm{S}}{{\rm{O}}_2}\)the oxidation number of oxygen is\( - 2\).
So, the oxidation number of sulfur is \( + 4\).
\(s{p^2}\)hybridization
What is the oxidation state of .
b) In\({\rm{S}}{{\rm{O}}_3}\)the oxidation number of oxygen is\( - 2\).
So, the oxidation number of sulfur is \( + 6\).
\(s{p^2}\)hybridization
What is the oxidation state of \({{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}\).
c) In\({{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}\)the oxidation number of hydrogen is\( + 1\), while oxygen is\( - 2\).
So, the oxidation number of sulfur is \( + 6\).
\(s{p^3}\)hybridization
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