Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 4: 4.12 CYL (page 201)

Which is the limiting reactant when 5.00 g of H2 and 10 g of O2 react to form water?

Short Answer

Expert verified

O2 is the limiting reactant

Step by step solution

01

Calculating moles of both of them

The balanced equation is as follows

\(2{H_2} + {O_2} \to 2{H_2}O\)

So, moles of H2

\(\begin{array}{l} = \frac{{{\rm{Given}}\,{\rm{mass}}}}{{{\rm{Molecular}}\,{\rm{weight}}}}\\ = \frac{{5g}}{{2g}}\\ = 2.5\,{\rm{moles}}\end{array}\)

So, moles of O2

\(\begin{array}{l} = \frac{{{\rm{Given}}\,{\rm{mass}}}}{{{\rm{Molecular}}\,{\rm{weight}}}}\\ = \frac{{10g}}{{32g}}\\ = 0.3125\,{\rm{moles}}\end{array}\)

02

Determine the limiting reactant

From the balanced equation, we can see that 2 mol of H2 produces 2 mol of H2O

So, 2.5 mol of H2 will produce = 2.5 x 2/2= 2.5 moles of H2O

1 mol of O2 produces 2 mol of H2O

0.1325 mol will produce = 0.3125 x 2 /1= 0.625 moles of H2O

As the amount of O2 is much smaller than H2. Hence the limiting reactant is O2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What volume of 0.600 M HCl is required to react completely with 2.50 g of sodium hydrogen carbonate?

\({\rm{NaHC}}{{\rm{O}}_{3(aq)}}{\rm{ + HC}}{{\rm{l}}_{(aq)}}{\rm{ }} \to {\rm{ NaC}}{{\rm{l}}_{(aq)}}{\rm{ + C}}{{\rm{O}}_{2(aq)}}{\rm{ + }}{{\rm{H}}_2}{{\rm{O}}_{({\rm{l}})}}\)

Complete and balance the following acid-base equations:

(a)HCl gas reacts with solidCa(OH)2

(b) A solution ofSr(OH)2is added to a solution ofHNO3.

What mass of gallium oxide Ga2O3 can be prepared from 29 g of gallium metal? The equation for the reaction is \(4Ga + 3{O_2} \to 2G{a_2}{O_3}\)

Classify the following as acid-base reaction or oxidation-reduction reactions.

(a)\(N{a_2}S\left( {aq} \right) + 2HCl\left( {aq} \right) \to 2NaCl\left( {aq} \right) + {H_2}S\left( g \right)\)

(b)\(2Na\left( s \right) + 2HCl\left( {aq} \right) \to 2NaCl\left( {aq} \right) + {H_2}\left( g \right)\)

(c)\(Mg\left( s \right) + C{l_2}\left( g \right) \to MgC{l_2}\left( s \right)\)

(d)\(MgO\left( s \right) + 2HCl\left( {aq} \right) \to MgC{l_2}\left( {aq} \right) + {H_2}O\left( l \right)\)

(e)\({K_3}P\left( s \right) + 2{O_2}\left( g \right) \to {K_3}P{O_4}\left( s \right)\)

(f)\(3KOH\left( {aq} \right) + {H_3}P{O_4}\left( {aq} \right) \to {K_3}P{O_4}\left( {aq} \right) + 3{H_2}O\left( l \right)\)

Fill in the blank with a single chemical formula for a covalent compound that will balance the equation:
See all solutions

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Read Explanation

Nuclear Chemistry

Read Explanation

Chemical Analysis

Read Explanation

Physical Chemistry

Read Explanation

Kinetics

Read Explanation

Chemical Reactions

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free