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Chapter 4: 4.14 (page 206)

A 20.00ml sample of aqueous oxalic acid H2C2O4 was titrated with a 0.09113M solution of potassium permanganate KMnO4,

\(2MnO_4^ - \left( {aq} \right) + 5{H_2}{C_2}{O_4}\left( {aq} \right) + 6{H^ + } \to 10C{O_2}\left( g \right) + 2M{n^{2 + }}\left( {aq} \right) + 8{H_2}O\left( l \right)\)

A volume of 23.24 ml was required to reach the endpoint. What is the oxalic acid molarity?

Short Answer

Expert verified

The molarity of oxalic acid is 0.2648M

Step by step solution

01

Given data

From the given equation we can get the mole ratio of H2C2O4:KMnO4=C2O4:MnO4-= 5:2

02

Calculating millimoles

Millimoles of KMnO4=0.09113mmol/ml x 23.24 ml= 2.1179 mmol

Millimoles of Oxalic acid = 2.1179 mol x 5/2 = 5.29475 mmol = 5.295 mmol (rounding off)

Molarity of oxalic acid = 5.295/20ml=0.26475M= 0.2648M (rounding off)

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