Write the net ionic equation representing the neutralization of any strong acid with an ionic hydroxide.
(Hint: Consider the ions produced when a strong acid is dissolved in water)

We will be taking NaOH, a strong base and HCl, a strong acid. So, they will be dissociating completely into their cation and anion in an aqueous solution.

\(\begin{array}{l}NaOH\left( {aq} \right) \to N{a^ + }\left( {aq} \right) + O{H^ - }\left( {aq} \right).\\HCl\left( {aq} \right) + {H_2}O\left( l \right) \to {H_3}{O^ + }\left( {aq} \right) + C{l^ - }\left( {aq} \right).\end{array}\)

After dissociating into their ions, the hydroxide ion and the hydrogen ion will combine to form water.

\({H_3}{O^ + }\left( {aq} \right) + C{l^ - }\left( {aq} \right) + N{a^ + }\left( {aq} \right) + O{H^ - }\left( {aq} \right) \to N{a^ + }\left( {aq} \right) + C{l^ - }\left( {aq} \right) + {H_2}O\left( l \right).\)

After cancelling the common ions, we get the equation as shown below:

\({H_3}{O^ + }\left( {aq} \right) + O{H^ - }\left( {aq} \right) \to 2{H_2}O\left( l \right).\)