In an acidic solution hydrogen peroxide reacts with Fe+2 to produce Fe+3 and water. Write a balanced equation for this reaction.

Short Answer

Expert verified

Answer

The balanced equation will be

\({H_2}{O_2}\left( {aq} \right) + 2{H^ + }\left( {aq} \right) + 2F{e^{2 + }}\left( {aq} \right) \to 2{H_2}O\left( l \right) + 2F{e^{3 + }}\)

Step by step solution

01

Writing half-reaction

The oxidation half-reaction is:\(F{e^{2 + }}\left( {aq} \right) \to F{e^{3 + }}\left( {aq} \right) + {e^ - }\)

The reduction half-reaction is: \(2{H^ + }\left( {aq} \right) + 2{e^ - } \to 2{H_2}O\left( l \right)\)

02

Balancing the equation

The oxidation half-reaction is multiplied by 2 to balance the number of electrons:

\(2F{e^{2 + }}\left( {aq} \right) \to 2F{e^{3 + }}\left( {aq} \right) + 2{e^ - }\)

03

Adding both the equation

Adding both the oxidation and reduction half-reactions, the following was obtained:

\({H_2}{O_2}\left( {aq} \right) + 2{H^ + }\left( {aq} \right) + 2F{e^{2 + }} \to 2{H_2}O\left( l \right) + 2F{e^{3 + }}\left( {aq} \right)\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Titration of a 20.0-mL sample of acid rain required 1.7 mL of 0.0811MNaOH to reach the end point. If we assume that the acidity of the rain is due to the presence of sulfuric acid, what was the concentration of sulfuric acid in this sample of rain?

Classify the following as acid-base reaction or oxidation-reduction reactions.

(a)\(N{a_2}S\left( {aq} \right) + 2HCl\left( {aq} \right) \to 2NaCl\left( {aq} \right) + {H_2}S\left( g \right)\)

(b)\(2Na\left( s \right) + 2HCl\left( {aq} \right) \to 2NaCl\left( {aq} \right) + {H_2}\left( g \right)\)

(c)\(Mg\left( s \right) + C{l_2}\left( g \right) \to MgC{l_2}\left( s \right)\)

(d)\(MgO\left( s \right) + 2HCl\left( {aq} \right) \to MgC{l_2}\left( {aq} \right) + {H_2}O\left( l \right)\)

(e)\({K_3}P\left( s \right) + 2{O_2}\left( g \right) \to {K_3}P{O_4}\left( s \right)\)

(f)\(3KOH\left( {aq} \right) + {H_3}P{O_4}\left( {aq} \right) \to {K_3}P{O_4}\left( {aq} \right) + 3{H_2}O\left( l \right)\)

Write the net ionic equation representing the neutralization of any strong acid with an ionic hydroxide.
(Hint: Consider the ions produced when a strong acid is dissolved in water)

Write a balanced equation for the decomposition of ammonium nitrate to form molecular nitrogen, molecular oxygen and water. (Hint Balance oxygen last, since it is present in more than one molecule on the right side of the equation)

How many milliliters of a 0.1500-M solution of KOH will be required to titrate 40.00 mL of a 0.0656-M solution of H3PO4?

\({{\rm{H}}_3}{\rm{P}}{{\rm{O}}_{4({\rm{aq}})}}{\rm{ + 2KO}}{{\rm{H}}_{({\rm{aq}})}}{\rm{ }} \to {\rm{ }}{{\rm{K}}_2}{\rm{HP}}{{\rm{O}}_{4({\rm{aq}})}}{\rm{ + 2}}{{\rm{H}}_2}{{\rm{O}}_{({\rm{l}})}}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free