The balanced molecular equations, write the complete ionic and net ionic equations for the following

(a)\({K_2}{C_2}{O_4}\left( {aq} \right) + Ba{\left( {OH} \right)_2}\left( {aq} \right) \to 2KOH\left( {aq} \right) + B{a_2}{C_2}{O_4}\)

(b)\(Pb{\left( {N{O_3}} \right)_2}\left( {aq} \right) + {H_2}S{O_4}\left( {aq} \right) \to PbS{O_4} + 2HN{O_3}\)

(c)\(CaC{O_3}\left( s \right) + {H_2}S{O_4}\left( {aq} \right) \to CaS{O_4} + C{O_2} + {H_2}O\)

The complete ionic equation is represented by:

\(2{K^ + }\left( {aq} \right) + {C_2}O_4^{2 - }\left( {aq} \right) + B{a^{2 + }}\left( {aq} \right) + 2O{H^ - }\left( {aq} \right) \to 2{K^ + }\left( {aq} \right)2O{H^ - }\left( {aq} \right) + Ba{C_2}{O_4}.\)

The spectator ions, and the potassium and hydroxide ions, on removal givethe net ionic equation as shown below:

\({C_2}O_4^{2 - }\left( {aq} \right) + B{a^{2 + }}\left( {aq} \right) \to Ba{C_2}{O_4}\left( s \right).\)

The complete ionic equation is represented by:

\(P{b^{2 + }}\left( {aq} \right) + 2N{O_3}^ - \left( {aq} \right) + 2{H^ + }\left( {aq} \right) + SO_4^{2 - }\left( {aq} \right) \to PbS{O_4}\left( s \right) + 2{H^ + }\left( {aq} \right) + 2NO_3^ - \left( {aq} \right).\)

The spectator ions, and the hydrogen and nitrate ions, on removal give the net ionic equation as given below:

\(P{b^{2 + }}\left( {aq} \right) + SO_4^{2 - }\left( {aq} \right) \to PbS{O_4}\left( s \right).\)

The complete ionic equation is represented by:

\(C{a^{2 + }}\left( s \right) + CO_3^{2 - }\left( s \right) + 2{H^ + }\left( {aq} \right) + SO_4^{2 - }\left( {aq} \right) \to CaS{O_4}\left( s \right) + C{O_2}\left( g \right) + {H_2}O\left( l \right).\)

There are no spectator ions in the above equation as all the ions undergo physical or chemical change.

Solid calcium ions react with dissolved sulfate ions giving solid calcium sulfate.

Solid carbonate ion reacts with dissolved hydrogen ions giving gaseous carbon dioxide and liquid water.

Hence, the net ionic equation and the complete ionic equations are identical.