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Chapter 4: Q15E (page 216)

Silver can be separated from gold because silver dissolves in nitric acid while gold does not. Is the dissolution of silver in nitric acid an acid-base reaction or an oxidation-reduction reaction? Explain your answer.

Short Answer

Expert verified

It is an oxidation-reduction reaction.

The balanced equations for the dissolution areas given below:

\(\begin{aligned}{}3Ag\left( s \right) + 4HN{O_3}\left( {Cold\& diluted} \right) \to 3AgN{O_3}\left( {aq} \right) + NO + 2{H_2}O\left( l \right)\\Ag\left( s \right) + 2HN{O_3}\left( {hot\& concentrated} \right) \to AgN{O_3}\left( {aq} \right) + N{O_2} + {H_2}O\left( l \right)\end{aligned}\)

Step by step solution

01

Reaction between silver and cold, dilute nitric acid

The corresponding balanced equation is as follows:

\(3Ag\left( s \right) + 4HN{O_3}\left( {Cold\& diluted} \right) \to 3AgN{O_3}\left( {aq} \right) + NO + 2{H_2}O\left( l \right)\)

In this case, silver is oxidised from 0 to +1 state and nitrogen reduced from +5 to +2 state (NO).

02

Reaction between silver and hot,concentrated nitric acid

The corresponding balanced equation is as follows:

\(Ag\left( s \right) + 2HN{O_3}\left( {hot\& concentrated} \right) \to AgN{O_3}\left( {aq} \right) + N{O_2} + {H_2}O\left( l \right)\)

In this case, silver is oxidised from 0 to +1 state and nitrogen reduced from+5 to +4 state (NO2)

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Most popular questions from this chapter

Write a balanced equation for the decomposition of ammonium nitrate to form molecular nitrogen, molecular oxygen and water. (Hint Balance oxygen last, since it is present in more than one molecule on the right side of the equation)

Balance the following equations:

\(\begin{array}{l}\left( a \right)\,Ag\left( s \right) + {H_2}S\left( g \right) + {O_2}\left( g \right) \to A{g_2}S\left( s \right) + {H_2}O\left( l \right)\\\left( b \right)\,{P_4}\left( s \right) + {O_2}\left( g \right) \to {P_4}{O_{10}}\left( s \right)\\\left( c \right)\,Pb\left( s \right) + {H_2}O\left( l \right) + {O_2}\left( g \right) \to Pb{\left( {OH} \right)_2}\left( s \right)\\\left( d \right)\,Fe\left( s \right) + {H_2}O\left( l \right) \to F{e_3}{O_4}\left( s \right) + {H_2}\left( g \right)\\\left( e \right)\,S{c_2}{O_3}\left( s \right) + S{O_3}\left( g \right) \to S{c_2}{\left( {S{O_4}} \right)_3}\left( s \right)\\\left( f \right)\,C{a_3}{\left( {P{O_4}} \right)_2}\left( {aq} \right) + {H_3}P{O_4}\left( {aq} \right) \to Ca{\left( {{H_2}P{O_4}} \right)_2}\left( {aq} \right)\\\left( g \right)\,Al\left( s \right) + {H_2}S{O_4}\left( {aq} \right) \to A{l_2}{\left( {S{O_4}} \right)_3}\left( s \right) + {H_2}\left( g \right)\\\left( h \right)\,TiC{l_4}\left( s \right) + {H_2}O\left( g \right) \to Ti{O_2}\left( s \right) + HCl\left( g \right)\end{array}\)

Write a balanced molecular equation describing each of the following chemical reactions.

(a) Solid calcium carbonate is heated and decomposes to solid calcium oxide and carbon dioxide gas

(b)Gaseous butane reacts with diatomic oxygen gas to yield gaseous carbon dioxide and water vapor

(c)Aqueous solution of magnesium chloride and sodium hydroxide react to produce solid magnesium hydroxide and aqueous sodium chloride

(d) Water vapor reacts with sodium metal to produce solid sodium hydroxide and hydrogen gas.

What mass of gallium oxide Ga2O3 can be prepared from 29 g of gallium metal? The equation for the reaction is \(4Ga + 3{O_2} \to 2G{a_2}{O_3}\)

How many molecules of the sweetener saccharin can be prepared from 30 C atoms, 25 H atoms, 12 O atoms, 8 S atoms, and 14 N atoms?
See all solutions

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