Chapter 4: Q74E (page 223)
How many molecules of C2H4Cl2 can be prepared from 15 C2H4molecules and 8 Cl2molecules?
Short Answer
8 molecules of\({C_2}{H_4}C{l_2}\)can be prepared from 15 C2H4molecules and 8 Cl2molecules
Chapter 4: Q74E (page 223)
How many molecules of C2H4Cl2 can be prepared from 15 C2H4molecules and 8 Cl2molecules?
8 molecules of\({C_2}{H_4}C{l_2}\)can be prepared from 15 C2H4molecules and 8 Cl2molecules
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AgNO3(aq) + NaCl(aq)⟶AgCl(s) + NaNO3(aq)
Determine the oxidation state of the elements in the following compounds:
(a)\(NaI\)
(b)\(GdC{l_3}\)
(c)\(LiN{O_3}\)
(d)\({H_2}Se\)
(e)\(M{g_2}Si\)
(f)\(Rb{O_2}\), rubidium superoxide
(g)\(HF\)
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