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Chapter 4: Q75E (page 223)

How many molecules of the sweetener saccharin can be prepared from 30 C atoms, 25 H atoms, 12 O atoms, 8 S atoms, and 14 N atoms?

Short Answer

Expert verified

4 molecules of the sweetener saccharin can be prepared from 30 C atoms, 25 H atoms, 12 O atoms, 8 S atoms, and 14 N atoms

Step by step solution

01

Given data

From the figure it can be identified one Saccharine molecule contains 7 carbon atoms, one nitrogen atom, five hydrogen atoms, three oxygen atoms, one sulfur atom.

02

Determine number of molecules of saccharine

There is total 30 carbon atoms then as each molecule of saccharine contains 7 carbon atoms. So only four molecules of saccharine possible.

There is total 25 hydrogen atoms Also, each molecule of saccharine contains five hydrogen atoms then four molecules contain 20 hydrogen atoms. So, four molecules of saccharine possible.

There is total 12 oxygen atoms Also, each molecule of saccharine contains three oxygen atoms then four molecules contain 12 oxygen atoms. So only four molecules of saccharine possible.

There is a total of 14 nitrogen atom. Each molecule of saccharine contains one nitrogen atoms then four molecules contain 4 nitrogen atoms. So, four molecules of saccharine possible.

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Most popular questions from this chapter

Write a balanced equation for the decomposition of ammonium nitrate to form molecular nitrogen, molecular oxygen and water. (Hint Balance oxygen last, since it is present in more than one molecule on the right side of the equation)

Diatomic chlorine and sodium hydroxide(lye) are commodity chemicals produced in large quantities, along with diatomic hydrogen via the electrolysis of brine according to the following unbalanced equation:

\[NaCl\left( {aq} \right) + {H_2}O\left( l \right) \to NaOH\left( {aq} \right) + {H_2}\left( g \right) + C{l_2}\left( g \right).\]

Write balanced molecular, complete ionic, and net ionic equations for this process.

Outline the steps needed to solve the following problem, then do the calculations. Ether,\({\left( {{C_2}{H_5}} \right)_2}O\), which was originally used as an anesthetic but has been replaced by safer and more effective medications, is prepared by the reaction of ethanol with sulfuric acid.\(2{C_2}{H_5}OH + {H_2}S{O_4} \to \left( {{C_2}{H_5}} \right)2O + {H_2}S{O_4} \cdot {H_2}O\)What is the percent yield of ether if 1.17 L (d = 0.7134 g/mL) is isolated from the reaction of 1.500 L of C2H5OH (d = 0.7894 g/mL)?

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(a) What is the difference between these types of equations?

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